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How many moles are there in 200 grams of Calcium Carbonate?
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
How many grams of calcium chloride will be produced when 30.0 g of calcium carbonate are combined with 12.0 g of hydrochloric acid?
To find the amount of calcium chloride produced, first calculate the moles of calcium carbonate and hydrochloric acid using their molar masses. Then, determine the limiting reactant and use stoichiometry to find the moles of calcium chloride produced. Finally, convert moles of calcium chloride to grams using its molar mass.
How do you solve for how many grams are in 2.38 moles of calcium carbonate?
To convert moles to grams, you need to use the molar mass of calcium carbonate (CaCO3). The molar mass of CaCO3 is approximately 100.1 g/mol. To calculate the grams in 2.38 moles of CaCO3, you would multiply the number of moles (2.38) by the molar mass (100.1 g/mol), which gives you approximately 238 grams.
How many ions of calcium present in 40 grams of calcium carbonate?
In calcium carbonate, the molar mass is 100.1 g/mol. The molar mass of calcium is 40.08 g/mol. Therefore, the percentage of calcium in calcium carbonate is 40.08/100.1 * 100 = 40%. Thus, in 40 grams of calcium carbonate, there are 40% of calcium, which is equivalent to 40/40.08 = 0.997 moles of calcium. Since calcium forms 1+ ions, there are 0.997 * 6.022 * 10^23 = 6.02 * 10^23 ions of calcium present.
How many moles of carbon dioxide would be produced if 2.5 mole of Calcium carbonate is consumed?
1 mole of calcium carbonate produces 1 mole of carbon dioxide when it decomposes. Therefore, if 2.5 moles of calcium carbonate is consumed, 2.5 moles of carbon dioxide will be produced.
How many moles of calcium carbonate are in 1.719 grams?
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
How many grams are in 1.25 moles of calcium carbonate?
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
How many moles are there in 200 grams of Calcium Carbonate?
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
How many moles of calcium are in 42.5 grams calcium?
42,5 grams calcium is equivalent to 1,06 moles.
How many moles of calcium carbonate are in one roll tums that contain 12 tablets?
Assuming each Tums tablet contains 500 mg of calcium carbonate, there is a total of 6 grams of calcium carbonate in one roll of Tums (12 tablets x 500 mg). To calculate the number of moles, divide the mass by the molar mass of calcium carbonate (100.09 g/mol), yielding around 0.06 moles of calcium carbonate in one roll of Tums.
How many moles of carbon are in 3.5 moles of calcium carbonate?
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
How many moles are there in 120 grams of calcium?
120 grams of calcium contain 2,994 moles.
How many moles of stomach acid would be neutralized by one tablet of regular strength maalox that contains 600 mg of calcium carbonate?
To calculate the number of moles of stomach acid neutralized by calcium carbonate, you first need to convert the mass of calcium carbonate (600 mg) to grams (0.6 g). Then, use the molar mass of calcium carbonate (100.09 g/mol) to find the number of moles. Finally, use the balanced chemical equation to determine the moles of stomach acid neutralized.
How many grams of calcium chloride will be produced when 30.0 g of calcium carbonate are combined with 12.0 g of hydrochloric acid?
To find the amount of calcium chloride produced, first calculate the moles of calcium carbonate and hydrochloric acid using their molar masses. Then, determine the limiting reactant and use stoichiometry to find the moles of calcium chloride produced. Finally, convert moles of calcium chloride to grams using its molar mass.
How many moles of carbon are in 3.5 moles of calcium carbonate?
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
How do you solve for how many grams are in 2.38 moles of calcium carbonate?
To convert moles to grams, you need to use the molar mass of calcium carbonate (CaCO3). The molar mass of CaCO3 is approximately 100.1 g/mol. To calculate the grams in 2.38 moles of CaCO3, you would multiply the number of moles (2.38) by the molar mass (100.1 g/mol), which gives you approximately 238 grams.
How many moles present in 7.68 grams of calcium nitride?
7,68 grams of calcium nitride is equal to 0,052 moles.
