To answer this we must first find the molar mass of calcium carbonate. CaCO3
Now that we have the molar mass we can find how many grams there are:
Assuming each Tums tablet contains 500 mg of calcium carbonate, there is a total of 6 grams of calcium carbonate in one roll of Tums (12 tablets x 500 mg). To calculate the number of moles, divide the mass by the molar mass of calcium carbonate (100.09 g/mol), yielding around 0.06 moles of calcium carbonate in one roll of Tums.
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
To calculate the number of moles of stomach acid neutralized by calcium carbonate, you first need to convert the mass of calcium carbonate (600 mg) to grams (0.6 g). Then, use the molar mass of calcium carbonate (100.09 g/mol) to find the number of moles. Finally, use the balanced chemical equation to determine the moles of stomach acid neutralized.
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
2,8 moles of calcium carbonate have 240,208 g.
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
42,5 grams calcium is equivalent to 1,06 moles.
Assuming each Tums tablet contains 500 mg of calcium carbonate, there is a total of 6 grams of calcium carbonate in one roll of Tums (12 tablets x 500 mg). To calculate the number of moles, divide the mass by the molar mass of calcium carbonate (100.09 g/mol), yielding around 0.06 moles of calcium carbonate in one roll of Tums.
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
120 grams of calcium contain 2,994 moles.
To calculate the number of moles of stomach acid neutralized by calcium carbonate, you first need to convert the mass of calcium carbonate (600 mg) to grams (0.6 g). Then, use the molar mass of calcium carbonate (100.09 g/mol) to find the number of moles. Finally, use the balanced chemical equation to determine the moles of stomach acid neutralized.
To find the amount of calcium chloride produced, first calculate the moles of calcium carbonate and hydrochloric acid using their molar masses. Then, determine the limiting reactant and use stoichiometry to find the moles of calcium chloride produced. Finally, convert moles of calcium chloride to grams using its molar mass.
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
To convert moles to grams, you need to use the molar mass of calcium carbonate (CaCO3). The molar mass of CaCO3 is approximately 100.1 g/mol. To calculate the grams in 2.38 moles of CaCO3, you would multiply the number of moles (2.38) by the molar mass (100.1 g/mol), which gives you approximately 238 grams.
7,68 grams of calcium nitride is equal to 0,052 moles.