To answer this we must first find the molar mass of calcium carbonate. CaCO3
Now that we have the molar mass we can find how many grams there are:
234 grams :)
28 grams calcium oxide (1 mole CaO/56.08 grams) = 0.50 moles CaO =============
.06 moles
5
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
2,8 moles of calcium carbonate have 240,208 g.
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
42,5 grams calcium is equivalent to 1,06 moles.
120 grams of calcium contain 2,994 moles.
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
No. of moles=wt. of substance/molecular wt. hence, wt. of substance= 2.38*100=238
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
234 grams :)
1,5 moles of potassium carbonate have 276,41 g.
7,68 grams of calcium nitride is equal to 0,052 moles.