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To answer this we must first find the molar mass of calcium carbonate. CaCO3

  • Ca= 40.08g
  • C=12.01g
  • O= 16.00g (we have three oxygens so 16.00x3 is 48.00g)
  • 40.08+12.01+48.00= 100.09 g

Now that we have the molar mass we can find how many grams there are:

  • 1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3
  • Therefore we'd have about 125 grams of CaCO3
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