.06 moles
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
The molar ratio between calcium carbonate and calcium oxide is 1:1. So, 25 moles of calcium carbonate will produce 25 moles of calcium oxide. The molar mass of calcium oxide is 56.08 g/mol, so the mass of calcium oxide produced will be 25 moles * 56.08 g/mol = 1402 g.
This question is solved with the help of mole concept . 1 mole of anhydrous calcium carbonate weighs 40+12+48=100 gm . 1.25 mole of similar anhydrous calcium carbonate will be 100* 1.25 = 125 gm
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
2,8 moles of calcium carbonate have 240,208 g.
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
The molar ratio between calcium carbonate and calcium oxide is 1:1. So, 25 moles of calcium carbonate will produce 25 moles of calcium oxide. The molar mass of calcium oxide is 56.08 g/mol, so the mass of calcium oxide produced will be 25 moles * 56.08 g/mol = 1402 g.
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. Therefore, the mass of 0.5 moles of calcium carbonate would be 0.5 mol x 100.09 g/mol = 50.045 grams.
1 mole of calcium carbonate produces 1 mole of carbon dioxide when it decomposes. Therefore, if 2.5 moles of calcium carbonate is consumed, 2.5 moles of carbon dioxide will be produced.
This question is solved with the help of mole concept . 1 mole of anhydrous calcium carbonate weighs 40+12+48=100 gm . 1.25 mole of similar anhydrous calcium carbonate will be 100* 1.25 = 125 gm
Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.
The molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol. To find the mass of 0.5 moles of CaCO3, you would multiply the molar mass by the number of moles: 0.5 moles x 100.09 g/mol = 50.045 g. Therefore, the mass of 0.5 moles of calcium carbonate is 50.045 grams.
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen