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The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.

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How many moles of oxygen atoms are in 4.25 moles of calcium carbonate the chief constituent of seashells?

Calcium Carbonate (CaCO3)I mol CaCO3 contains 3 mol Oxygen atomsso 4.25 mol CaCO3 will have 12.75 mol Oxygen Atoms.


How many moles of oxygen are in one mole of calcium carbonate?

1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen


How many moles of carbon are in 3.5 moles of calcium carbonate?

3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles


How many carbon atoms are in a molecule of calcium carbonate CaCO3?

A mole of H2 molecules contains 6.023 x 10^(23) H2 molecules or 2 moles of H atoms (since each molecules has 2 atoms). A mole of CaCO3 (calcium carbonate) has one mole (Avogadro number) of Ca atoms, one mole of C atoms and 3 moles of O atoms.


What is the mass of 0.5 moles of calcium carbonate (CaCO3)?

The molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol. To find the mass of 0.5 moles of CaCO3, you would multiply the molar mass by the number of moles: 0.5 moles x 100.09 g/mol = 50.045 g. Therefore, the mass of 0.5 moles of calcium carbonate is 50.045 grams.


How many grams are in 2.8 moles of calcium carbonate?

2,8 moles of calcium carbonate have 240,208 g.


How many moles of calcium carbonate are in 1.719 grams?

Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.


A rolaid tablet contains calcium carbonate if 44.55 ml of 0.448 M hydrochloric acid is required to neutralize one tablet how many milligrams of calcium carbonate are in a rolaids tablet?

44.55 ML solution x 1L/1000ML X 0.448M HCL/1L solution X 1mole CaCO3/2 mole HCL= 0.0099792 M CaCO3 0.0099792 M CaCO3 x 217gCaCO3/1 mole CaCO3= 2.17g CaCO3 X 1000MG/1g=2170 mg of calcium carbonate are in a rolaids tablet?


What is the mass of 0.5 moles of calcium carbonate?

The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. Therefore, the mass of 0.5 moles of calcium carbonate would be 0.5 mol x 100.09 g/mol = 50.045 grams.


How many o atoms are present in 50gram of caco3?

There are 2 oxygen atoms in one molecule of CaCO3. To calculate the number of oxygen atoms in 50 grams of CaCO3, you first need to find the number of moles of CaCO3 using its molar mass. Then, multiply the number of moles by the number of atoms of oxygen per molecule of CaCO3 (2) to find the total number of oxygen atoms.


How many grams are in 1.25 moles of calcium carbonate?

To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3


How many moles of carbon are in 3.5 moles of calcium carbonate?

The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.