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One mole of calcium contains Avogadro's number of atoms, which is approximately 6.022 x 10^23 atoms.

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1y ago

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How many atoms are in 125 grams of Calcium?

Well, Ca has an atomic mass of 40, so one mole of Ca (6.022x1023 atoms) equals 40g.To get 5kg of Ca, you would times the 40g (one mole) by 125.5kg of Ca has 125x(6.022x1023), or602200000000000000000000 atoms.


How many carbon atoms are in a molecule of calcium carbonate CaCO3?

A mole of H2 molecules contains 6.023 x 10^(23) H2 molecules or 2 moles of H atoms (since each molecules has 2 atoms). A mole of CaCO3 (calcium carbonate) has one mole (Avogadro number) of Ca atoms, one mole of C atoms and 3 moles of O atoms.


How many atoms are in 6 moles of calcium?

A mole contains 6.022 x 10^23 atoms, which is also known as Avogadro's number, and this number is same for each element. So, there are 2 x (6.022 x 10^23) = 12.044 x 10^23 atoms in 2 moles of Calcium.


How does the number of atoms in one mole of beryllium compare with the number of atoms in one mole of magnesium?

One mole of any element contains Avogadro's number of atoms, which is approximately 6.022 x 10^23 atoms. Beryllium and magnesium are both in Group 2 of the periodic table, so they have the same number of atoms in one mole.


How many moles of oxygen are in one mole of calcium carbonate?

1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen


How many atoms are in 115 grams of Calcium?

Avogadro's Number, 6.022 x 1023 gives the number of atoms in one mole. Calcium has an average atomic weight of 40.08 gmol-1 So one mole weighs 40.08 grams. 115 grams of Calcium will have (6.022 x 1023 / 40.08)*115 = 1.73 x 1024 atoms.


What does the number of atoms in one mole of each element do?

The number of atoms in one mole is the number of Avogadro: 6,022 140 857.10e23.


How many atoms are in 195 grams of calcium?

To find the number of atoms in 195 grams of calcium, you first need to calculate the number of moles of calcium using its molar mass. Calcium's molar mass is 40.08 g/mol, so there are 195g / 40.08 g/mol = 4.86 moles of calcium. Finally, one mole of calcium contains 6.022 x 10^23 atoms, so 4.86 moles x 6.022 x 10^23 atoms/mole = 2.95 x 10^24 atoms of calcium in 195 grams.


How many molecules of calcium carbonate are present in its one mole?

If its at STP (standard temperature & pressure) then i think 6 x 10^23 molecules


What characteristic does one mole of carbon have in common with one mole of sodium?

Both one mole of carbon and one mole of sodium contain Avogadro's number of atoms, which is approximately 6.02 x 10^23 atoms. This quantity is true for all elements or substances when considering one mole.


How many atoms of calcium are present in 60.8 g of calcium?

First you need to find how many moles of calcium that is. Since 1 mole of calcium is 40.078g you need to divide 60.8g by how much is one mole (60.8 / 40.078 = 1.517 moles). Once you know how many moles you have (1.517) you can find how many particles there are. There are 6.02 *10^23 atoms in one mole (Avagadro's number), so your final answer will be, 6.02*10^23 x 1.517 = 9.132 * 10^23


How many atoms are in one gram of calcium?

To work this out you need to know the atomic weight of calcium and Avogadros number, which is the number of atoms in a gram atom. Calcium has an atomic weight of 40.078. Therefore a gram ato is 40.078 grams which contains 6.02214129(27)×1023 atoms. 1g of calcium contains 6.02214129(27)×1023 / 40.078 1.502 X 1022