One mole of calcium contains Avogadro's number of atoms, which is approximately 6.022 x 10^23 atoms.
If its at STP (standard temperature & pressure) then i think 6 x 10^23 molecules
There are 6.02 x 10 ^ 23 atoms or molecules of a substance in one mole of that substance. This is Avogadro's number.
First, you need to figure out how many moles of calcium you have. One mole of calcium is 40.078g. So, divide 189g by 40.078. (189/40.078 = 4.716) Now, you can find out how many particles there are. There are 6.02*10^23 atoms in one mole. So, your answer will be 6.02*10^23 x 4.716 = 28.39 * 10^23.
6.02214076×1023
To calculate the number of atoms in a sample of calcium, you need to first determine the moles of calcium in 169 g. Then, you can use Avogadro's number (6.022 x 10^23 atoms per mole) to find the number of atoms. The atomic mass of calcium is 40.08 g/mol, so 169 g of calcium is approximately 4.22 moles. Multiplying this by Avogadro's number gives approximately 2.54 x 10^24 atoms in 169 g of calcium.
Well, Ca has an atomic mass of 40, so one mole of Ca (6.022x1023 atoms) equals 40g.To get 5kg of Ca, you would times the 40g (one mole) by 125.5kg of Ca has 125x(6.022x1023), or602200000000000000000000 atoms.
A mole of H2 molecules contains 6.023 x 10^(23) H2 molecules or 2 moles of H atoms (since each molecules has 2 atoms). A mole of CaCO3 (calcium carbonate) has one mole (Avogadro number) of Ca atoms, one mole of C atoms and 3 moles of O atoms.
A mole contains 6.022 x 10^23 atoms, which is also known as Avogadro's number, and this number is same for each element. So, there are 2 x (6.022 x 10^23) = 12.044 x 10^23 atoms in 2 moles of Calcium.
One mole of any element contains Avogadro's number of atoms, which is approximately 6.022 x 10^23 atoms. Beryllium and magnesium are both in Group 2 of the periodic table, so they have the same number of atoms in one mole.
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
Avogadro's Number, 6.022 x 1023 gives the number of atoms in one mole. Calcium has an average atomic weight of 40.08 gmol-1 So one mole weighs 40.08 grams. 115 grams of Calcium will have (6.022 x 1023 / 40.08)*115 = 1.73 x 1024 atoms.
The number of atoms in one mole is the number of Avogadro: 6,022 140 857.10e23.
To find the number of atoms in 195 grams of calcium, you first need to calculate the number of moles of calcium using its molar mass. Calcium's molar mass is 40.08 g/mol, so there are 195g / 40.08 g/mol = 4.86 moles of calcium. Finally, one mole of calcium contains 6.022 x 10^23 atoms, so 4.86 moles x 6.022 x 10^23 atoms/mole = 2.95 x 10^24 atoms of calcium in 195 grams.
If its at STP (standard temperature & pressure) then i think 6 x 10^23 molecules
Both one mole of carbon and one mole of sodium contain Avogadro's number of atoms, which is approximately 6.02 x 10^23 atoms. This quantity is true for all elements or substances when considering one mole.
First you need to find how many moles of calcium that is. Since 1 mole of calcium is 40.078g you need to divide 60.8g by how much is one mole (60.8 / 40.078 = 1.517 moles). Once you know how many moles you have (1.517) you can find how many particles there are. There are 6.02 *10^23 atoms in one mole (Avagadro's number), so your final answer will be, 6.02*10^23 x 1.517 = 9.132 * 10^23
To work this out you need to know the atomic weight of calcium and Avogadros number, which is the number of atoms in a gram atom. Calcium has an atomic weight of 40.078. Therefore a gram ato is 40.078 grams which contains 6.02214129(27)×1023 atoms. 1g of calcium contains 6.02214129(27)×1023 / 40.078 1.502 X 1022