6.02214076×1023
There are 1.5 x 10^24 representative particles in 2.5 moles, considering Avogadro's number (6.022 x 10^23) representative particles per mole.
mole
When 1.0 mole of O2 is completely consumed in the reaction to form NO, 1.0 mole of NO is produced since the balanced equation for the reaction is 2 O2 + 2 N2 -> 2 NO. This means that the mole ratio between O2 and NO is 1:1.
Do you mean this reaction? 2Mg + O2 -> 2MgO 4.11 moles Mg (1 mole O2/2 mole Mg) = 2.06 moles oxygen gas consumed --------------------------------------------------
1 mole of 02 gas has 12,044 281 714.1023 atoms.
A mole of oxygen atoms has a mass of approximately 16 grams. A mole of O2 has a mass of approximately 32 grams. A mole is 6.02 x 1023 particles and as such a mole of oxygen atoms has only half the mass of a mole of oxygen molecules.
1 mole of HgO produces 1 mole of O2 according to the balanced chemical equation for the reaction. Therefore, 0.440 moles of HgO will produce 0.440 moles of O2.
Also 0,1 mole carbon dioxide.
82.5 grams O2 (1 mole O2/32 grams)(6.022 X 10^23/1 mole O2) = 1.55 X 10^24 atoms of O2
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
The balanced equation for the reaction must be given to determine the molar ratio between O2 and P2O5. Without that information, it is not possible to determine the exact number of moles of P2O5 produced from 8.00 moles of O2.
There are 1.5 x 10^24 representative particles in 2.5 moles, considering Avogadro's number (6.022 x 10^23) representative particles per mole.
3 moles of O, so that must be 6 moles of O2
mole
One Mole, or Avogadro's Number, is 6.022 X 1023
2no12no plus o2?????Do you mean this decomposition equation?2NO --> N2 + O23.1 grams O2 (1 mole O2/32 grams)(2 moles NO/1 mole O2)(6.022 X 1023/1 mole NO)= 1.2 X 1023 atoms of nitric oxide needed============================( if this is not what you meant you can resubmit or contact me )
1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas