Also 0,1 mole carbon dioxide.
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The balanced equation for the reaction must be given to determine the molar ratio between O2 and P2O5. Without that information, it is not possible to determine the exact number of moles of P2O5 produced from 8.00 moles of O2.
The answer is one mole.
Balanced equation. C2H6O + 3O2 --> 2CO2 + 3H2O 0.274 moles C2H6O (2 moles CO2/1 mole C2H6O) = 0.548 moles carbon dioxide produced ============================
0,75 moles of nitrogen
If 1 mole of carbon reacts, 1 mole of CO is produced according to the balanced chemical equation for the reaction. Therefore, if 1.4 moles of carbon react, 1.4 moles of CO will be produced.
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mummy mole and daddy mole popped out a baby mole
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced
Balanced equation: 2Al + 3Cl2 -> 2AlCl3For every 3 moles of Cl2, 2 moles of AlCl3 is produced (Using the numbers in front of the compounds)Now set up a proportion: 3/2 = 0.30/?Cross Multiply: (2 X 0.30) / 3 = 0.20.2 moles of AlCl3 will be produced.
1 mole of calcium carbonate produces 1 mole of carbon dioxide when it decomposes. Therefore, if 2.5 moles of calcium carbonate is consumed, 2.5 moles of carbon dioxide will be produced.
1 mole of HgO produces 1 mole of O2 according to the balanced chemical equation for the reaction. Therefore, 0.440 moles of HgO will produce 0.440 moles of O2.
CO2 + 4H2 --> CH4 + 2H2O0.500 moles CO2 (1 mole CH4/1 mole CO2) = 0.500 moles CH40.500 moles CO2 (2 moles H2O/1 mole CO2) = 1.00 moles H2O-------------------------------------------------------------------------------------add= 1.50 moles total product====================
The balanced equation for the reaction must be given to determine the molar ratio between O2 and P2O5. Without that information, it is not possible to determine the exact number of moles of P2O5 produced from 8.00 moles of O2.
To calculate the moles of gas produced, first find the moles of Mg reacting by dividing the mass by the molar mass of Mg. Next, determine the mole ratio of Mg to gas produced from the balanced chemical equation of the reaction. Finally, multiply the moles of Mg by the mole ratio to find the moles of gas produced.
Glucose? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles water from one mole sugar.