1,4 moles of CO are produced.
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∙ 7y agoIf 1 mole of carbon reacts, 1 mole of CO is produced according to the balanced chemical equation for the reaction. Therefore, if 1.4 moles of carbon react, 1.4 moles of CO will be produced.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
Using the balanced equation 2 AlCl₃ + 3 Pb(NO₃)₂ → 3 PbCl₂ + 2 Al(NO₃)₃, the mole ratio between AlCl₃ and PbCl₂ is 2:3. Therefore, if 14 moles of AlCl₃ are consumed, 9.33 moles (14 moles / 2 * 3) of PbCl₂ will be produced.
None, unless there is metallic potassium in the reaction mixture. Assuming excess potassium metal is present then 14 moles of KBr can be produced. 7BaBr2 + excess potassium -----> 14KBr + 7 Ba
The heat of reaction per mole can be calculated by dividing the energy produced by the number of moles. In this case, 84 J of energy produced by 6 moles of the compound gives a heat of reaction of 14 J/mol.
84 J/6 moles = 14 J/mole = ∆H
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
Using the balanced equation 2 AlCl₃ + 3 Pb(NO₃)₂ → 3 PbCl₂ + 2 Al(NO₃)₃, the mole ratio between AlCl₃ and PbCl₂ is 2:3. Therefore, if 14 moles of AlCl₃ are consumed, 9.33 moles (14 moles / 2 * 3) of PbCl₂ will be produced.
None, unless there is metallic potassium in the reaction mixture. Assuming excess potassium metal is present then 14 moles of KBr can be produced. 7BaBr2 + excess potassium -----> 14KBr + 7 Ba
For every mole of potassium chlorate (KClO3) that decomposes, it produces 3 moles of oxygen (O2). Therefore, 14 moles of KClO3 will produce 14 x 3 = 42 moles of oxygen.
The heat of reaction per mole can be calculated by dividing the energy produced by the number of moles. In this case, 84 J of energy produced by 6 moles of the compound gives a heat of reaction of 14 J/mol.
84 J/6 moles = 14 J/mole = ∆H
1,0.10e9 atoms is equivalent to 0,166.10e-14 moles.
-14 J/Mol
There are 8 moles of P4O10, and each mole of P4O10 contains 4 moles of phosphorus atoms. Therefore, there are 32 moles of phosphorus atoms in 8 moles of P4O10.
The calculation is: Moles = Mass / Atomic Mass Moles = 0.085 / 17 Moles = 0.005 Atomic mass is 17 because ammonia is NH3, with N = 14, and H = 1. 14 + 1 + 1 + 1 = 17.
To calculate the cellular respiration rate in moles of glucose per minute, you need to convert the volume of CO2 produced into moles using the ideal gas law. Then, you can use the stoichiometry of the cellular respiration reaction to relate the moles of CO2 produced to moles of glucose consumed. Once you have both values, you can determine the rate of glucose consumption per minute.
There are 29/14, or just over 2 moles of nitrogen in 19 grams.