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84 J/6 moles = 14 J/mole = ∆H

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Viva Kub

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evelyn

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-14 J/mol

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Q: If 6 moles of a compound produce 84 j of energy what is the H reaction in jmol?
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If 6 moles of a compound produce 84 J of energy what is the H reaction in J mol?

-14 J/Mol


If 6 moles of a compound produce 84 J of energy what is the delta H reaction in jmol?

84 J/6 moles = 14 J/mole = ∆H


If 3 moles of a compound use 12 J of energy in a reaction what is the H reaction in kJmol?

12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole


If 6 moles of a compound produce 84 J of energy what is the Hreaction in Jmol?

-14 J/mol


What 6 moles of a compound produce 84 J of energy what is the Hreaction in Jmol?

-14 J/mol


How many moles of aluminum are required to produce 4 moles of hydrogen?

This is not a common reaction at standard temperature and pressure.


IF a reaction vessel contains 0.15 moles of LiOH and 0.08 moles of CO2 which compound is the limiting reagent?

Carbon dioxide is the limiting reagent.


What information in a balanced equation shows how many moles of a reactant are involved in the reaction?

This is the number before a chemical compound.


How many moles of O2 g are produced by the reaction of 156 g CO2 g with excess KO2?

The reaction of carbon dioxide and potassium oxide is 4KO2 + 2CO2 = 2K2CO3 + 3O2. 156 grams of CO2 is 3.54 moles, which will produce 5.31 moles of O2.


How do you find if you have 14.5 moles of N2 how many moles of H2 are theoretically needed to produce 22.5 moles of NH3 according to the reaction N2 plus 3H2 2NH3?

N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------


How many moles of PbClβ‚‚ are produced if 14 moles of AlCl₃ are consumed?

If the reaction were 2AlCl3 + 3Pb ---> 3PbCl2 + 2Al, then from this balanced equation, 14 moles of AlCl3 would produce 3/2 x 14 moles of PbCl2 = 21 moles of PbCl2.


How many moles of potassium chlorate are needed to produce 15 moles of oxygen?

Assuming a decomposition reaction with this equation: 2KClO3(s) --> 2KCl(s) + 3O2(g), the ratio is 2:3, and if you produce 15mol O2, then 10mol potassium chlorate are needed.