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If 3 moles of a compound use 24 J of energy in a reaction what is the Hreaction in Jmol A. -8 Jmol?
The enthalpy change for the reaction would be -8 J/mol, as it is the energy change per mole of the compound reacted.
If 6 moles of a compound produce 84 J of energy what is the H reaction in J mol?
-14 J/Mol
If 6 moles of a compound produce 84 J of energy what is the delta H reaction in jmol?
The enthalpy change (ΔH) per mole can be found by dividing the energy produced by the moles of the compound. In this case, ΔH = 84 J / 6 mol = 14 J/mol. Therefore, the enthalpy change per mole of the compound is 14 J/mol.
If 6 moles of a compound produce 84 j of energy what is the H reaction in jmol?
84 J/6 moles = 14 J/mole = ∆H
Which statement shows how to correctly convert from the mass of a compound in grams to the amount of that compound in moles?
To convert from the mass of a compound in grams to the amount of that compound in moles, you need to divide the mass of the compound in grams by its molar mass (which is found on the periodic table). This will give you the number of moles of the compound. The formula to use is: moles = mass (g) / molar mass.
What 6 moles of a compound produce 84 J of energy what is the Hreaction in Jmol?
-14 J/mol
If 3 moles of a compound use 24 J of energy in a reaction what is the Hreaction in Jmol A. -8 Jmol?
The enthalpy change for the reaction would be -8 J/mol, as it is the energy change per mole of the compound reacted.
If 6 moles of a compound produce 84 J of energy what is the H reaction in J mol?
-14 J/Mol
If 6 moles of a compound produce 84 J of energy what is the delta H reaction in jmol?
The enthalpy change (ΔH) per mole can be found by dividing the energy produced by the moles of the compound. In this case, ΔH = 84 J / 6 mol = 14 J/mol. Therefore, the enthalpy change per mole of the compound is 14 J/mol.
If 6 moles of a compound produce 84 j of energy what is the H reaction in jmol?
84 J/6 moles = 14 J/mole = ∆H
If 6 moles of a compound produce 84 j of energy what is the deltaHreaction jmol?
To find the enthalpy change (( \Delta H )) per mole of the compound, divide the total energy produced by the number of moles. In this case, ( \Delta H = \frac{84 , \text{J}}{6 , \text{moles}} = 14 , \text{J/mol} ). Therefore, the ( \Delta H ) for the reaction is 14 J/mol.
Which statement shows how to correctly convert from the mass of a compound in grams to the amount of that compound in moles?
To convert from the mass of a compound in grams to the amount of that compound in moles, you need to divide the mass of the compound in grams by its molar mass (which is found on the periodic table). This will give you the number of moles of the compound. The formula to use is: moles = mass (g) / molar mass.
How can one determine the empirical formula from moles in a chemical compound?
To determine the empirical formula from moles in a chemical compound, you first need to find the moles of each element present in the compound. Then, divide the moles of each element by the smallest number of moles to get the simplest whole number ratio. This ratio represents the empirical formula of the compound.
If 3 moles of a compound use 12 J of energy in a reaction what is the H reaction in kJmol?
12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole
How many moles of ethane does it take to produce 293 moles of H2O?
The answer is 97,66 moles.
How many moles of MgCl2 are there in 313 g of the compound?
Approx 3.29 moles.
How many moles of ammonia are produced from 12.0 moles of hydrogen?
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
