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-14 J/mol
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If 3 moles of a compound use 24 J of energy in a reaction what is the Hreaction in Jmol?
To find the enthalpy change (Hreaction) in J/mol, you divide the total energy used by the number of moles. Here, 24 J of energy is used for 3 moles of the compound. Therefore, Hreaction = 24 J / 3 moles = 8 J/mol.
If 3 moles of a compound use 24 J of energy ina reaction what is the Hreaction in Jmol?
To find the enthalpy change (ΔH) for the reaction in J/mol, you divide the total energy used by the number of moles. Given that 3 moles of the compound use 24 J of energy, you calculate ΔH as follows: ΔH = 24 J / 3 moles = 8 J/mol. Thus, the enthalpy change for the reaction is 8 J/mol.
If 6 moles of a compound produce 84 j of energy what is the deltaHreaction jmol?
To find the enthalpy change (( \Delta H )) per mole of the compound, divide the total energy produced by the number of moles. In this case, ( \Delta H = \frac{84 , \text{J}}{6 , \text{moles}} = 14 , \text{J/mol} ). Therefore, the ( \Delta H ) for the reaction is 14 J/mol.
If 6 moles of a compound produce 84 J of energy what is the change of H reaction in Jmol?
To find the change in enthalpy (ΔH) for the reaction in J/mol, divide the total energy produced by the number of moles. For 6 moles producing 84 J, ΔH = 84 J / 6 moles = 14 J/mol. Thus, the change in enthalpy for the reaction is 14 J/mol.
How many moles of ethane does it take to produce 293 moles of H2O?
The answer is 97,66 moles.
If 3 moles of a compound use 24 J of energy in a reaction what is the Hreaction in Jmol?
To find the enthalpy change (Hreaction) in J/mol, you divide the total energy used by the number of moles. Here, 24 J of energy is used for 3 moles of the compound. Therefore, Hreaction = 24 J / 3 moles = 8 J/mol.
If 6 moles of a compound produce 84 J of energy what is the Hreaction in Jmol?
The heat of reaction per mole can be calculated by dividing the energy produced by the number of moles. In this case, 84 J of energy produced by 6 moles of the compound gives a heat of reaction of 14 J/mol.
If 3 moles of a compound use 24 J of energy in a reaction what is the Hreaction in Jmol A. -8 Jmol?
The enthalpy change for the reaction would be -8 J/mol, as it is the energy change per mole of the compound reacted.
If 6 moles of a compound produce 84 J of energy what is the H reaction in J mol?
-14 J/Mol
If 6 moles of a compound produce 84 J of energy what is the delta H reaction in jmol?
The enthalpy change (ΔH) per mole can be found by dividing the energy produced by the moles of the compound. In this case, ΔH = 84 J / 6 mol = 14 J/mol. Therefore, the enthalpy change per mole of the compound is 14 J/mol.
If 6 moles of a compound produce 84 j of energy what is the H reaction in jmol?
84 J/6 moles = 14 J/mole = ∆H
If 6 moles of a compound produce 84 j of energy what is the deltaHreaction jmol?
To find the enthalpy change (( \Delta H )) per mole of the compound, divide the total energy produced by the number of moles. In this case, ( \Delta H = \frac{84 , \text{J}}{6 , \text{moles}} = 14 , \text{J/mol} ). Therefore, the ( \Delta H ) for the reaction is 14 J/mol.
If 6 moles of a compound produce 84 J of energy what is the change of H reaction in Jmol?
To find the change in enthalpy (ΔH) for the reaction in J/mol, divide the total energy produced by the number of moles. For 6 moles producing 84 J, ΔH = 84 J / 6 moles = 14 J/mol. Thus, the change in enthalpy for the reaction is 14 J/mol.
Which statement shows how to correctly convert from the mass of a compound in grams to the amount of that compound in moles?
To convert from the mass of a compound in grams to the amount of that compound in moles, you need to divide the mass of the compound in grams by its molar mass (which is found on the periodic table). This will give you the number of moles of the compound. The formula to use is: moles = mass (g) / molar mass.
How can one determine the empirical formula from moles in a chemical compound?
To determine the empirical formula from moles in a chemical compound, you first need to find the moles of each element present in the compound. Then, divide the moles of each element by the smallest number of moles to get the simplest whole number ratio. This ratio represents the empirical formula of the compound.
If 3 moles of a compound use 12 J of energy in a reaction what is the H reaction in kJmol?
12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole
How many moles of ethane does it take to produce 293 moles of H2O?
The answer is 97,66 moles.
