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If 3 moles of a compound use 24 J of energy in a reaction what is the Hreaction in Jmol?
To find the enthalpy change (Hreaction) in J/mol, you divide the total energy used by the number of moles. Here, 24 J of energy is used for 3 moles of the compound. Therefore, Hreaction = 24 J / 3 moles = 8 J/mol.
What 6 moles of a compound produce 84 J of energy what is the Hreaction in Jmol?
-14 J/mol
If 6 moles of a compound produce 84 J of energy what is the change of H reaction in Jmol?
To find the change in enthalpy (ΔH) for the reaction in J/mol, divide the total energy produced by the number of moles. For 6 moles producing 84 J, ΔH = 84 J / 6 moles = 14 J/mol. Thus, the change in enthalpy for the reaction is 14 J/mol.
If 6 moles of a compound produce 84 j of energy what is the deltaHreaction jmol?
To find the enthalpy change (( \Delta H )) per mole of the compound, divide the total energy produced by the number of moles. In this case, ( \Delta H = \frac{84 , \text{J}}{6 , \text{moles}} = 14 , \text{J/mol} ). Therefore, the ( \Delta H ) for the reaction is 14 J/mol.
IF a reaction vessel contains 0.15 moles of LiOH and 0.08 moles of CO2 which compound is the limiting reagent?
Carbon dioxide is the limiting reagent.
If 3 moles of a compound use 24 J of energy in a reaction what is the Hreaction in Jmol A. -8 Jmol?
The enthalpy change for the reaction would be -8 J/mol, as it is the energy change per mole of the compound reacted.
If 6 moles of a compound produce 84 J of energy what is the Hreaction in Jmol?
The heat of reaction per mole can be calculated by dividing the energy produced by the number of moles. In this case, 84 J of energy produced by 6 moles of the compound gives a heat of reaction of 14 J/mol.
What 6 moles of a compound produce 84 J of energy what is the Hreaction in Jmol?
-14 J/mol
If 6 moles of a compound produce 84 J of energy what is the H reaction in J mol?
-14 J/Mol
If 3 moles of a compound use 12 J of energy in a reaction what is the H reaction in kJmol?
12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole
If 6 moles of a compound produce 84 j of energy what is the H reaction in jmol?
84 J/6 moles = 14 J/mole = ∆H
If 6 moles of a compound produce 84 J of energy what is the delta H reaction in jmol?
The enthalpy change (ΔH) per mole can be found by dividing the energy produced by the moles of the compound. In this case, ΔH = 84 J / 6 mol = 14 J/mol. Therefore, the enthalpy change per mole of the compound is 14 J/mol.
If 6 moles of a compound produce 84 j of energy what is the deltaHreaction jmol?
To find the enthalpy change (( \Delta H )) per mole of the compound, divide the total energy produced by the number of moles. In this case, ( \Delta H = \frac{84 , \text{J}}{6 , \text{moles}} = 14 , \text{J/mol} ). Therefore, the ( \Delta H ) for the reaction is 14 J/mol.
IF a reaction vessel contains 0.15 moles of LiOH and 0.08 moles of CO2 which compound is the limiting reagent?
Carbon dioxide is the limiting reagent.
What information in a balanced equation shows how many moles of a reactant are involved in the reaction?
This is the number before a chemical compound.
What compound is 2nacl br2?
The compound 2NaCl + Br2 is not a specific compound itself. It represents a chemical reaction where two moles of sodium chloride (NaCl) react with one mole of bromine (Br2). The products of this reaction would be sodium bromide (NaBr) and possibly other byproducts depending on reaction conditions.
Which statement shows how to correctly convert from the mass of a compound in grams to the amount of that compound in moles?
To convert from the mass of a compound in grams to the amount of that compound in moles, you need to divide the mass of the compound in grams by its molar mass (which is found on the periodic table). This will give you the number of moles of the compound. The formula to use is: moles = mass (g) / molar mass.
