If 3 moles of a compound use 24 J of energy in a reaction, the H reaction is 8 J/mol.
Approx 3.29 moles.
The coefficient (in this case a 2) indicates the number of moles or molecules of the compound. So, 2NH3 means there are 2 moles or 2 molecules of ammonia (NH3).
There are 15 moles of ammonia sulfate in the reaction of 30.0 mol of NH3. This goes from the formula 2 NH3 H2so take away (NH4)2So4.
1
Lead(II) sulphate has the molecular formula of PbSO4. The molecular weight of PbSO4 is 303.3 grams per mole. A sample weight of 158.1 grams corresponds to .5213 moles of PbSO4.
The heat of reaction per mole can be calculated by dividing the energy produced by the number of moles. In this case, 84 J of energy produced by 6 moles of the compound gives a heat of reaction of 14 J/mol.
-14 J/Mol
The enthalpy change for the reaction would be -8 J/mol, as it is the energy change per mole of the compound reacted.
84 J/6 moles = 14 J/mole = ∆H
The enthalpy change (ΔH) per mole can be found by dividing the energy produced by the moles of the compound. In this case, ΔH = 84 J / 6 mol = 14 J/mol. Therefore, the enthalpy change per mole of the compound is 14 J/mol.
To find the enthalpy change (( \Delta H )) per mole of the compound, divide the total energy produced by the number of moles. In this case, ( \Delta H = \frac{84 , \text{J}}{6 , \text{moles}} = 14 , \text{J/mol} ). Therefore, the ( \Delta H ) for the reaction is 14 J/mol.
Carbon dioxide is the limiting reagent.
This is the number before a chemical compound.
The compound 2NaCl + Br2 is not a specific compound itself. It represents a chemical reaction where two moles of sodium chloride (NaCl) react with one mole of bromine (Br2). The products of this reaction would be sodium bromide (NaBr) and possibly other byproducts depending on reaction conditions.
-14 J/mol
To calculate the energy generated from freezing 2.5 g of water, we use the heat of fusion (Hfusion) of water, which is 6.03 kJ/mol. First, convert the mass of water to moles: (2.5 , \text{g} \div 18.02 , \text{g/mol} \approx 0.1386 , \text{mol}). Then, multiply the number of moles by the heat of fusion: (0.1386 , \text{mol} \times 6.03 , \text{kJ/mol} \approx 0.835 , \text{kJ}). Thus, approximately 0.835 kJ of energy is released when 2.5 g of water freezes.
To convert from the mass of a compound in grams to the amount of that compound in moles, you need to divide the mass of the compound in grams by its molar mass (which is found on the periodic table). This will give you the number of moles of the compound. The formula to use is: moles = mass (g) / molar mass.