answersLogoWhite

0


Best Answer

If the reaction were 2AlCl3 + 3Pb ---> 3PbCl2 + 2Al, then from this balanced equation, 14 moles of AlCl3 would produce 3/2 x 14 moles of PbCl2 = 21 moles of PbCl2.

User Avatar

Wiki User

7y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

7y ago

21 moles of lead chloride are produced

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many moles of PbCl₂ are produced if 14 moles of AlCl₃ are consumed?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is this compound called PbCl 4?

lead (IV) oxide


The oxidation number of cholrine in the compound PbCI has to be?

-1. However PbCl is not a compound of lead- PbCl2 and PbCl4 are


Which of the following compounds contains the lead(II) ion?

Examples are: PbO, PbNO3, PbCl, PbS, etc.


What has the author Torstein Arnfinn Utigard written?

Torstein Arnfinn Utigard has written: 'Wetting behaviour of molten PbCl r alkali chloride mixtures'


Why does adding sodium chloride to a saturated solution of lead chloride reduce the solubility of PbCl 2?

Equilibrium is pushed toward the left in the equation. PbCl2(s) <=> Pb^2+(aq)+2Cl^-(aq).


Calculate the number of moles present in each of the following samples.6.684e13 pg of fluorine atoms 2.435e6 mg of magnesium 3.2e-3 kg of lead(II) chloride 6.684e-5 Mg of fluorine 2.31e-9 Gg of carbon disulfide 4.91e9 ng of aluminum sulfate?

umber of Moles= Molar Mass (in g/mol) Mass (in grams) ​ First, you'll need to know the molar mass of the substance in question. Here are the calculations for each sample: 6.684e13 pg of fluorine atoms: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e13 pg = 6.684e-6 g Number of moles = (6.684e-6 g) / (19 g/mol) ≈ 3.52e-7 moles 2.435e6 mg of magnesium: Molar mass of magnesium (Mg) = 24.305 g/mol Mass in grams = 2.435e6 mg = 2.435 g Number of moles = (2.435 g) / (24.305 g/mol) ≈ 0.1001 moles 3.2e-3 kg of lead(II) chloride: Molar mass of lead(II) chloride (PbCl₂) = 207.2 g/mol Mass in grams = 3.2e-3 kg = 3200 g Number of moles = (3200 g) / (207.2 g/mol) ≈ 15.45 moles 6.684e-5 Mg of fluorine: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e-5 Mg = 6.684e-5 g Number of moles = (6.684e-5 g) / (19 g/mol) ≈ 3.52e-6 moles 2.31e-9 Gg of carbon disulfide: Molar mass of carbon disulfide (CS₂) = 76.143 g/mol Mass in grams = 2.31e-9 Gg = 2.31e15 g Number of moles = (2.31e15 g) / (76.143 g/mol) ≈ 3.03e12 moles 4.91e9 ng of aluminum sulfate: Molar mass of aluminum sulfate (Al₂(SO₄)₃) = 342.15 g/mol Mass in grams = 4.91e9 ng = 4.91e-6 g Number of moles = (4.91e-6 g) / (342.15 g/mol) ≈ 1.43e-8 moles