umber of Moles=
Molar Mass (in g/mol)
Mass (in grams)
First, you'll need to know the molar mass of the substance in question. Here are the calculations for each sample:
6.684e13 pg of fluorine atoms:
Molar mass of fluorine (F) = 19 g/mol
Mass in grams = 6.684e13 pg = 6.684e-6 g
Number of moles = (6.684e-6 g) / (19 g/mol) ≈ 3.52e-7 moles
2.435e6 mg of magnesium:
Molar mass of magnesium (Mg) = 24.305 g/mol
Mass in grams = 2.435e6 mg = 2.435 g
Number of moles = (2.435 g) / (24.305 g/mol) ≈ 0.1001 moles
3.2e-3 kg of lead(II) chloride:
Molar mass of lead(II) chloride (PbCl₂) = 207.2 g/mol
Mass in grams = 3.2e-3 kg = 3200 g
Number of moles = (3200 g) / (207.2 g/mol) ≈ 15.45 moles
6.684e-5 Mg of fluorine:
Molar mass of fluorine (F) = 19 g/mol
Mass in grams = 6.684e-5 Mg = 6.684e-5 g
Number of moles = (6.684e-5 g) / (19 g/mol) ≈ 3.52e-6 moles
2.31e-9 Gg of carbon disulfide:
Molar mass of carbon disulfide (CS₂) = 76.143 g/mol
Mass in grams = 2.31e-9 Gg = 2.31e15 g
Number of moles = (2.31e15 g) / (76.143 g/mol) ≈ 3.03e12 moles
4.91e9 ng of aluminum sulfate:
Molar mass of aluminum sulfate (Al₂(SO₄)₃) = 342.15 g/mol
Mass in grams = 4.91e9 ng = 4.91e-6 g
Number of moles = (4.91e-6 g) / (342.15 g/mol) ≈ 1.43e-8 moles
To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.
Magnesium is in period 3 of the periodic table.
The reaction of boron with magnesium can be represented by the following equation: 3Mg + 2B -> Mg3B2
The compound is magnesium chloride. It consists of one magnesium atom and two chlorine atoms.
To calculate the percentage of magnesium by mass in a compound, divide the mass of magnesium by the total mass of the compound, then multiply by 100. Percentage of magnesium by mass = (mass of magnesium / total mass of compound) * 100.
By starting with a balanced equation. Mg + 2HCl -> MgCl2 + H2 when they say sufficient magnesium they imply that magnesium is in excess and HCl limits and drives the reaction, or that both are equal in molarity/mass 54.75 g HCl (1 mole HCl/36.458 g)(1 mole MgCl2/2 mole HCl)(95.21 g/1 mole MgCl2) = 71.49 grams magnesium chloride produced -----------------------------------------------------------
The answer is 9,3945.1023 molecules.
Na
The atomic mass of Mg is 24.3 amu.
3Mg + N2 --> Mg3N2 Magnesium and nitrogen react to form magnesium nitride.
Deficiency is associated with hypertension
Magnesium is the correct spell....Whatever, if you add Magnesium (Mg) to Water (H2o), it will form Magnesium Hydroxide. The following equation is:- Mg+O2+H2O=Mg(OH)2