Yes
To determine the amount of oxygen, we first find the amount of magnesium by subtracting the given 20.0 grams of magnesium oxide from the total. Given that the molar mass of magnesium oxide is 40.3 g/mol and that of magnesium is 24.3 g/mol, we calculate the amount of oxygen by adjusting accordingly. This process gives us the weight ratio of magnesium oxide to oxygen.
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
By starting with a balanced equation. Mg + 2HCl -> MgCl2 + H2 when they say sufficient magnesium they imply that magnesium is in excess and HCl limits and drives the reaction, or that both are equal in molarity/mass 54.75 g HCl (1 mole HCl/36.458 g)(1 mole MgCl2/2 mole HCl)(95.21 g/1 mole MgCl2) = 71.49 grams magnesium chloride produced -----------------------------------------------------------
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
To find the number of moles in 444 grams of magnesium chloride, you first need to calculate the molar mass of magnesium chloride. The molar mass of MgCl2 is about 95.21 g/mol. Next, calculate the number of moles by dividing the given mass by the molar mass: 444 g / 95.21 g/mol ≈ 4.66 moles of magnesium chloride.
To determine the amount of oxygen, we first find the amount of magnesium by subtracting the given 20.0 grams of magnesium oxide from the total. Given that the molar mass of magnesium oxide is 40.3 g/mol and that of magnesium is 24.3 g/mol, we calculate the amount of oxygen by adjusting accordingly. This process gives us the weight ratio of magnesium oxide to oxygen.
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
2
By starting with a balanced equation. Mg + 2HCl -> MgCl2 + H2 when they say sufficient magnesium they imply that magnesium is in excess and HCl limits and drives the reaction, or that both are equal in molarity/mass 54.75 g HCl (1 mole HCl/36.458 g)(1 mole MgCl2/2 mole HCl)(95.21 g/1 mole MgCl2) = 71.49 grams magnesium chloride produced -----------------------------------------------------------
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.637 grams Mg / (24.3 grams) = .191 moles Mg
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
If 3 grams of magnesium are used to form 4 grams of magnesium oxide, then 1 gram of oxygen is used in the reaction. This means 1 gram of oxygen remains unused.
The atomic mass of magnesium (Mg) is approximately 24.305 grams per mole.
24.31 grams of magnesium is one mole of magnesium, so that is 6.022 X 1023 atoms of magnesium.