lead (IV) oxide
The oxidation number of chlorine in the compound PbCl is -1. Each chlorine atom in PbCl has an oxidation number of -1, as lead has a fixed oxidation number of +2.
The oxidation number of chlorine in the compound PbCl is -1. Lead (Pb) has an oxidation number of +2, so the overall charge of the compound is neutral. Chlorine typically has an oxidation number of -1 in binary compounds.
Lead (II) chloride
SO3 is a covalent compound, not ionic. It is called sulfur trioxide.
The compound AIPO₄ is called aluminum phosphate. It is an inorganic compound composed of aluminum, phosphorus, and oxygen atoms in a specific ratio.
The oxidation number of chlorine in the compound PbCl is -1. Each chlorine atom in PbCl has an oxidation number of -1, as lead has a fixed oxidation number of +2.
The oxidation number of chlorine in the compound PbCl is -1. Lead (Pb) has an oxidation number of +2, so the overall charge of the compound is neutral. Chlorine typically has an oxidation number of -1 in binary compounds.
The correct name for the compound with the formula PbCl₄ is lead(IV) chloride. In this compound, lead (Pb) has a +4 oxidation state, which is indicated by the Roman numeral IV in its name. The chloride ions (Cl⁻) each carry a -1 charge, leading to the overall neutral charge of the compound.
PbCl2 is lead(II) chloride, PbCl4 is lead(IV) chloride
Lead (II) chloride
carbon tetrachloride
In the chemical formula PbCl₄ (lead(IV) chloride), there are four chlorine (Cl) atoms, which are non-metal atoms. Therefore, there are a total of four non-metal atoms in PbCl₄.
SO3 is a covalent compound, not ionic. It is called sulfur trioxide.
The compound Xe4F9 is called xenon nonafluoride. It is a chemical compound composed of xenon and fluorine atoms in a 4:9 ratio.
The compound AIPO₄ is called aluminum phosphate. It is an inorganic compound composed of aluminum, phosphorus, and oxygen atoms in a specific ratio.
Using the balanced equation 2 AlCl₃ + 3 Pb(NO₃)₂ → 3 PbCl₂ + 2 Al(NO₃)₃, the mole ratio between AlCl₃ and PbCl₂ is 2:3. Therefore, if 14 moles of AlCl₃ are consumed, 9.33 moles (14 moles / 2 * 3) of PbCl₂ will be produced.
maybe Boron(II) Silicide(4-)