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There are 29/14, or just over 2 moles of nitrogen in 19 grams.

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17y ago

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What is the amount of water when3gram of hydrogen reacts with 29gram of oxygen Which is the limiting reagent and calculate the amount of water formed in grams?

To determine the amount of water formed when 3 grams of hydrogen reacts with 29 grams of oxygen, we first need to identify the limiting reagent. The balanced chemical equation for the reaction is 2H₂ + O₂ → 2H₂O. The molar mass of hydrogen is approximately 2 g/mol, so 3 grams of hydrogen corresponds to 1.5 moles of H₂. The molar mass of oxygen is about 32 g/mol, so 29 grams of oxygen corresponds to 0.90625 moles of O₂. Since the reaction requires 2 moles of H₂ for every mole of O₂, we need 3.0 moles of H₂ for the available 1 mole of O₂, meaning hydrogen is the limiting reagent. Therefore, 1.5 moles of H₂ will produce 1.5 moles of water (H₂O), which weighs approximately 27 grams (since the molar mass of water is about 18 g/mol).