The atomic weight of Li is 6.941 g/mol
The mass of the sample is 55.2 g
This means that:
55.2/6.941=7.95 moles (rounded number)
Multiplying this with Avogadro's number (6.022*1023)
7.95*6.022*1023=4.79*1024 atoms.
There you have your answer.
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
12.7 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 1.10 X 10^24 atoms of lithium
I assume you mean; 0.01456 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 1.263 X 10^21 atoms of lithium
3,00 moles of Li have 18,066422571.10e23 atoms.
Lithium hydroxide has three atoms in it, one each of lithium, hydrogen, and oxygen. Also note that lithium is Li, not LI. Little details matter to chemists. A capital I means iodine.
2.59 atoms?? Oh well. 2.59 atoms Li (1mol Li/6.022 X 10^23 )(6.941 grams Li/1mol Li ) = 2.98 X 10^-23 grams
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
4.32x10(-2)g Li
12.7 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 1.10 X 10^24 atoms of lithium
I assume you mean; 0.01456 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 1.263 X 10^21 atoms of lithium
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
1 mole Li = 6.94g Li = 6.022 x 1023 atoms Li 27.0g Li x 6.022 x 1023 atoms Li/6.94g Li = 2.34 x 1024 atoms Li
How many lithium atoms are in 10.56 g of lithium
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
3,00 moles of Li have 18,066422571.10e23 atoms.
Lithium hydroxide has three atoms in it, one each of lithium, hydrogen, and oxygen. Also note that lithium is Li, not LI. Little details matter to chemists. A capital I means iodine.
4.7 mole Li (6.022 X 10^23/1 mole Li) = 2.8 X 10^24 atoms Li