4.32x10(-2)g Li
2.59 atoms?? Oh well. 2.59 atoms Li (1mol Li/6.022 X 10^23 )(6.941 grams Li/1mol Li ) = 2.98 X 10^-23 grams
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
The molecular formula for lithium chlorate is Li₂ClO₃, which consists of two lithium (Li) atoms, one chlorine (Cl) atom, and three oxygen (O) atoms. Given the molar mass of 73.8 grams/mole, this is consistent with the calculated molar mass of Li₂ClO₃, which is approximately 73.89 grams/mole. Thus, the molecular formula is indeed Li₂ClO₃.
Well, honey, if we're talking about lithium (Li) and you've got 55.2 grams of it, you're looking at approximately 7.4 x 10^23 atoms. That's a whole lotta Li atoms in your hands. Hope you've got a plan for all that atomic power!
How many lithium atoms are in 10.56 g of lithium
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
The molar mass of Li = 6.941 g/mol
Li: atomic mass 6.941F: atomic mass 18.998Lithium fluoride is made up of these two elements. Its balanced formula is LiF (Li+1F-1). Adding both its atomic masses equals 25.939. Therefore one mole of LiF is equal to 25.939 grams. So, 1.5 moles of LiF is equal to 38.90 grams.
15g Li * (1mol Li / 6.941g Li) = 2.16 mol Li
From the periodic table, lithium has an atomic weight of 6.941. The molar mass of an element is the atomic weight in grams. Therefore, 1 mole Li = 6.941g Li Therefore, moles Li = 15g Li X 1 mole Li/6.941g Li = 2.2 moles Li
To find the number of lithium atoms, you would need to know the molar mass of lithium (6.94 g/mol) and then use the formula: Number of atoms = (0.01456 g / 6.94 g/mol) * Avogadro's number Avogadro's number is 6.022 x 10^23 atoms/mol.