How many lithium atoms are in 10.56 g of lithium
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
15g Li * (1mol Li / 6.941g Li) = 2.16 mol Li
The balanced chemical equation for the reaction of lithium and nitrogen to form lithium nitride is 6Li + N2 -> 2Li3N. From the equation, it shows that 1 mole of N2 reacts with 6 moles of Li. Therefore, to react with 0.500 mol of Li, you would need 0.500 mol of N2.
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
3.977 mol
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
3,00 moles of Li have 18,066422571.10e23 atoms.
No moles of BaCO3 are found in any amount of Li.
1 mole of Li₂O contains 2 moles of lithium (Li) atoms and 1 mole of oxygen (O) atoms. Therefore, in 1 mole of Li₂O, there are a total of 3 moles of atoms.
4.7 mole Li (6.022 X 10^23/1 mole Li) = 2.8 X 10^24 atoms Li
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
Oh, dude, you're hitting me with that chemistry question! So, like, one mole of any element contains Avogadro's number of atoms, which is 6.022 x 10^23. In this case, you've got 4.5 moles of Li, so you just multiply that by Avogadro's number to get the total number of Li atoms. That's like... a lot of Li atoms, man.
1 mole Li = 6.94g Li = 6.022 x 1023 atoms Li 27.0g Li x 6.022 x 1023 atoms Li/6.94g Li = 2.34 x 1024 atoms Li
The balanced chemical equation for the reaction is 3Li + H3PO4 -> Li3PO4 + 3H2. The mole ratio is 1:1 between Li and H3PO4. Therefore, 4 moles of H3PO4 will react with 4 moles of Li.
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
From the periodic table, lithium has an atomic weight of 6.941. The molar mass of an element is the atomic weight in grams. Therefore, 1 mole Li = 6.941g Li Therefore, moles Li = 15g Li X 1 mole Li/6.941g Li = 2.2 moles Li