4.7 mole Li (6.022 X 10^23/1 mole Li)
= 2.8 X 10^24 atoms Li
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
3,00 moles of Li have 18,066422571.10e23 atoms.
Remember the Avogadro Number. 1 moles = 6.022 x 10^(23) atoms/molecules. So for 0.106 moles lithium it is 0.106 X 6.022 x 10^(23) = 6.38 x 10^(22) atoms (Li). or stringing it out 6,380,000,000,000,000,000,000 atoms
Remember the Avogadro Number. This is the number of atoms in an element or the number of molecules in a compound. for an amount of 1 mole. So 1 mole(Li) it is 6.022 x 10^(23) atoms . In Numbers 602,200,000,000,000,000,000,000
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
1 mole of Li₂O contains 2 moles of lithium (Li) atoms and 1 mole of oxygen (O) atoms. Therefore, in 1 mole of Li₂O, there are a total of 3 moles of atoms.
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
1 mole Li = 6.94g Li = 6.022 x 1023 atoms Li 27.0g Li x 6.022 x 1023 atoms Li/6.94g Li = 2.34 x 1024 atoms Li
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
3,00 moles of Li have 18,066422571.10e23 atoms.
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
Remember the Avogadro Number. 1 moles = 6.022 x 10^(23) atoms/molecules. So for 0.106 moles lithium it is 0.106 X 6.022 x 10^(23) = 6.38 x 10^(22) atoms (Li). or stringing it out 6,380,000,000,000,000,000,000 atoms
Remember the Avogadro Number. This is the number of atoms in an element or the number of molecules in a compound. for an amount of 1 mole. So 1 mole(Li) it is 6.022 x 10^(23) atoms . In Numbers 602,200,000,000,000,000,000,000
How many lithium atoms are in 10.56 g of lithium
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
The molecular formula for lithium chlorate is Li₂ClO₃, which consists of two lithium (Li) atoms, one chlorine (Cl) atom, and three oxygen (O) atoms. Given the molar mass of 73.8 grams/mole, this is consistent with the calculated molar mass of Li₂ClO₃, which is approximately 73.89 grams/mole. Thus, the molecular formula is indeed Li₂ClO₃.
To find the number of lithium atoms, you would need to know the molar mass of lithium (6.94 g/mol) and then use the formula: Number of atoms = (0.01456 g / 6.94 g/mol) * Avogadro's number Avogadro's number is 6.022 x 10^23 atoms/mol.