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To find the number of moles of CaBr2 in 5.0 grams, you first need to calculate the molar mass of CaBr2. The molar mass of CaBr2 is 200.8 g/mol. Divide the given mass by the molar mass to find the number of moles: 5.0 g / 200.8 g/mol = 0.025 moles of CaBr2. Since there is one mole of CaBr2 for every two moles of CaBr, you have half of that amount in moles of CaBr: 0.025 moles / 2 = 0.0125 moles of CaBr.
1 mole of P4O10 reacts with 6 moles of water to produce 4 moles of H3PO4. Therefore, 10.0 moles of water will produce (10/6)*4 moles of H3PO4. To convert moles to grams, multiply the number of moles by the molar mass of H3PO4.
To find the number of moles of K2SO4 in 15.0 grams, first calculate the molar mass of K2SO4 (K: 39.10 g/mol, S: 32.07 g/mol, O: 16.00 g/mol). Molar mass of K2SO4 = 2(39.10) + 32.07 + 4(16.00) = 174.26 g/mol Now, divide the given mass by the molar mass to find the number of moles: 15.0 g / 174.26 g/mol = 0.086 moles of K2SO4
To find the number of moles in 1 kg of C2H6O2, we first need to calculate the molar mass of C2H6O2: (212.01) + (61.01) + (2*16.00) = 62.07 g/mol. Then, we convert 1 kg to grams: 1 kg = 1000 g. Finally, we divide the mass by the molar mass to find the number of moles: 1000 g / 62.07 g/mol = 16.12 moles.
To calculate the number of grams in 1.11 moles of manganese sulfate (Mn3(SO4)7), you need to find the molar mass of the compound. The molar mass of Mn3(SO4)7 is approximately 678.88 g/mol. Therefore, 1.11 moles of Mn3(SO4)7 would be equal to 1.11 moles x 678.88 g/mol ≈ 753.38 grams.
To determine the number of moles of water needed to react with 1.7 moles of Li2O, we can use the balanced chemical equation for the reaction: [ \text{Li}_2\text{O} + 2\text{H}_2\text{O} \rightarrow 2\text{LiOH}. ] From the equation, 1 mole of Li2O reacts with 2 moles of water. Therefore, 1.7 moles of Li2O would require 1.7 x 2 = 3.4 moles of water.
The molar mass of Li2O is 29,88 g (the sum of atomic weights of 2Li and 1O).
The balanced chemical equation for the reaction between water and Li2O is 2 H2O + Li2O -> 2 LiOH. It shows that 2 moles of water react with 1 mole of Li2O. So, 2.2 moles of Li2O would require 4.4 moles of water for complete reaction.
134.1 grams
This suggests the substance is lithium oxide (Li2O). The molar mass of Li2O is 29.88 g/mol. Therefore, 62g of Li2O is equivalent to 2.07 moles (62g / 29.88 g/mol = 2.07 mol).
There are 2 oxygen atoms in Li2O. This is derived from the chemical formula of lithium oxide - Li2O - which indicates that there are 2 atoms of lithium and 1 atom of oxygen in each molecule.
LiO DOES not exist. Lithium oxide has the formula 'Li2O'.
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
The chemical formula for lithium oxide is Li2O
what is the cation of Be3N2
The chemical formula for lithium oxide is Li2O.
Li2O is the chemical formula of dilithium oxide.