Not many!
5.0 grams CaBr2 (1 mole/199.88 grams CaBr2)
= 0.025 moles CaBr2
Multiple the moles of K2SO4 by the molecular weight of 174.2592 grams. That should equal 210.85 grams.
moles = weight in grams / molecular weight = 72 / 180 = 0.4 moles
For this you need the atomic mass of Au. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.355 grams Au / (197.0 grams) = 1.80 moles Au
just short of a mole. moles is mass/molar mass. mass is 42, molar mass is 44. 42/44
molec weight is 151g/mol. 1.11 moles x 151g/mol is 167.61g Moles is mass / molecular mass
0,31 moles of anhydrous CaBr2 is equal to 61,966 g.
2.5 mol x 10-2
1.2 Kilograms Calcium bromide (1000 grams/1 kilogram)(1 mole CaBr2/199.88 grams) = 6.0 moles calcium bromide
16 grams of oxygen how many moles is 0,5 moles.
3.5M / 1000, x 150 = how many moles you need. = .525 moles. moles = mass / molec mass. molec mass if cabr2 is 199.86 g/mol. .525 x 199.86 is 104.93g CaBr2
That is a lot of calcium bromide we are dealing with. The formula mass of calcium bromide, CaBr2 is 40.1 + 2(79.9) = 199.9.Amount of CaBr2 = (7.4 x 1000)/199.9 = 32.0mol There are 32 moles of calcium bromide in a 7.4kg pure sample.
.75 moles times 64 grams/mols = 48 grams
53 grams ÷ 18.01 grams/mole = 2.94 moles
180 grams of water is 10 moles of water.
222,6 grams of iodine is equivalent to 1,754 moles.
370 grams of mercury is equal to 1,844 moles.
380.7 grams of iodineis equivalent to 3 moles.