Not many!
5.0 grams CaBr2 (1 mole/199.88 grams CaBr2)
= 0.025 moles CaBr2
To find the number of moles in 355 grams of Au, you need to divide the given mass by the molar mass of gold (Au). The molar mass of Au is approximately 197 grams/mol. Therefore, 355 grams of Au is equivalent to 355/197 = approximately 1.80 moles of Au.
To calculate the number of moles in 42 grams of CO2, we first need to find the molar mass of CO2, which is approximately 44 grams per mole. Then, divide the given mass by the molar mass to find the number of moles. In this case, 42 grams of CO2 is equivalent to 42/44 = 0.955 moles.
The molar mass of fructose is approximately 180.16 g/mol. To find the mass in grams, you would multiply the number of moles (1.20 mol) by the molar mass (180.16 g/mol). Therefore, 1.20 moles of fructose would be 216.19 grams.
To find the number of moles of K2SO4 in 15.0 grams, first calculate the molar mass of K2SO4 (K: 39.10 g/mol, S: 32.07 g/mol, O: 16.00 g/mol). Molar mass of K2SO4 = 2(39.10) + 32.07 + 4(16.00) = 174.26 g/mol Now, divide the given mass by the molar mass to find the number of moles: 15.0 g / 174.26 g/mol = 0.086 moles of K2SO4
1 mole of P4O10 reacts with 6 moles of water to produce 4 moles of H3PO4. Therefore, 10.0 moles of water will produce (10/6)*4 moles of H3PO4. To convert moles to grams, multiply the number of moles by the molar mass of H3PO4.
To find the number of grams of CaBr2 in 0.31 moles, you first calculate the molar mass of CaBr2, which is approximately 199.89 g/mol. Then, you can multiply the number of moles (0.31 moles) by the molar mass to find the grams: 0.31 moles x 199.89 g/mol = 61.97 grams of CaBr2.
Well, darling, if you want to know how many moles of CaBr2 are in 5.0 grams, you just need to divide the mass by the molar mass of CaBr2. The molar mass of CaBr2 is approximately 199.89 g/mol, so 5.0 grams of CaBr2 is roughly 0.025 moles. Hope that helps, sugar!
To find the number of moles in 1.2 kg of calcium bromide, you first need to determine the molar mass of calcium bromide (CaBr2), which is approximately 199.89 g/mol. Then convert the mass of 1.2 kg to grams (1200 g). Finally, divide the mass in grams by the molar mass to find the number of moles. In this case, 1200g / 199.89g/mol ≈ 6 moles of calcium bromide.
That is a lot of calcium bromide we are dealing with. The formula mass of calcium bromide, CaBr2 is 40.1 + 2(79.9) = 199.9.Amount of CaBr2 = (7.4 x 1000)/199.9 = 32.0mol There are 32 moles of calcium bromide in a 7.4kg pure sample.
16 grams of oxygen how many moles is 0,5 moles.
To calculate the mass of calcium bromide needed, you would first find the number of moles needed using the equation moles = Molarity * Volume (in liters). Then, you would use the molar mass of calcium bromide to convert moles to grams. The molar mass of calcium bromide is 199.89 g/mol.
53 grams ÷ 18.01 grams/mole = 2.94 moles
120 grams of calcium contain 2,994 moles.
1,8 grams of fluorine is equivalent to 0,0947 moles.
0.377 grams of Kr is equal to 0,0045 moles.
124 grams of ethane is equal to 4,124 moles.
320 grams of oxygen is the equivalent of 10 moles.