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just short of a mole. moles is mass/molar mass. mass is 42, molar mass is 44. 42/44

Q: How many moles are in 42 grams of CO2?

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There are 1000 grams in one kilogram. Therefore, 42 kilograms is equal to 42 x 1000 = 42000 grams.

42 pounds is 19051g

42 kilograms = 92.6 pounds.

120000g = 264.55 pounds (rounded from 264.554715).

You have .07 Liters of 3 moles/Liter of Na2CO3. So if you do .07*3*2 (you multiply by two because there are TWO Na+ ions in Na2CO3) you get .42 moles of Na+. Then you do the same with NaHCO3. So, .03*1 is equal to .03 moles of Na+. Adding .42 with .03 will give you .45, the number of moles of Na+ of the whole solution. Since you are looking for concentration (which is moles if solute divided by Liters of solution), you must divide by .1 Liters (you get that by adding .07 and .03 of the two liquids that compose the solution) to get 4.5 Molar. That is the answer!

Related questions

there is .42 moles

1.8 moles

The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.

As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.

42 grams is 1.48 ounces.

42 kilograms = 42000 grams (1 kilogram is 1000 grams)

42 grams of water is approximately 2.963 tablespoons.

1 kilogram = 1,000 grams 42 kilograms = 42,000 grams

42

There are 1000 grams in one kilogram. Therefore, 42 kilograms is equal to 42 x 1000 = 42000 grams.

According to this balanced equation:Na2O + H2O --> 2NaOH42 moles Na2O react with 42 moles H2O

First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g