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(1kg C2H6O2 )(1000g/1kg)(1mol/62g) = 16.1 moles
Wiki User
∙ 10y ago
Wiki User
∙ 8y agoThe answer is 17,11 moles.
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How many kilograms are there in grams?
1 kg = 1000 grams 1 gram = 0.001 kg
How many pounds are in 1 Kilogram or 1 kg?
1 Kilogram (kg) = 2.2046244201837775 Pounds
How many mL in 1 KG of liquid silicone?
1 kg silicone equals how many mls
How many Gram in KG?
1 kg = 1000 g
How many grams our in a kilogram?
1 kg = 1000 grams 1 gram = 0.001 kg
How many moles are in 1 kg of CF2Cl2?
1 kg of difluorodichloromethane is equivalent to 8,27 moles.
How many moles are in 1.0 kilograms of NaCl?
1 kg NaCl contain 17,112 moles.
How many moles of sodium are in 5.13 kg of sodium?
Quite a few! 5.13 kilograms sodium (1000 grams/1 kg)(1 mole Na/22.99 grams) = 223 moles of sodium =================
Calculate with clear arrangements how many moles of oxygen are needed to burn 1 kg of ethane and 1 kg of ethanol, respectively?
nothing
What is molality of a solution?
It is the number of moles of solute in 1 kg of solvent.
What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?
4 mol over 0.800 kg
How many kg in one kg?
Depends on the molecule. Look in the periodic table at the atomic weights. This number is the grams per mole. Carbon for example has 12 grams in each mole.
How many the mole of CO 2 contains?
atomic weight of carbon dioxide is 2 * 16 + 12 = 44 1 kg = 1000 g 1 kg of co2 has 1000/44 = 22.7 moles yeh i think that's wrong lol isn't it 3.37E25?
What is the molality of a solution composed of 38.0 g of cane sugar (C12H 22O11) dissolved in 175 g of water?
molality = moles solute/kg solvent moles solute = 38.0g x 1 mol/342 g = 0.111 moles kg solvent = 175 g x 1kg/1000g = 0.175 kg molality = 0.111 moles/0.175 kg = 0.635 m
How many moles of KF are contained in 347 g of water in a 0.175 m KF solution?
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
0.33 mol/kg (apex)
What is the mole fraction of solute in a 3.71 m aqueous solution?
molal = m = moles solute/kg solvent. Assuming water as the solvent 1 kg = 1000 g/18g/mole = 55.56 moles H2O. Moles solute = 3.71 moles. Total moles present = 55.56 + 3.71 = 59.27 moles.Mole fraction solute = 3.71/59.27 = 0.0626
