(1kg C2H6O2 )(1000g/1kg)(1mol/62g) = 16.1 moles
1 kg = 1000 grams 1 gram = 0.001 kg
1 14 kg is approximately 3.08 lbs.
1 kg = 1000 g
1000g is 1kg.
1 kg = 1000 g1 kg = 1000 g1 kg = 1000 g1 kg = 1000 g1 kg = 1000 g1 kg = 1000 g
Quite a few! 5.13 kilograms sodium (1000 grams/1 kg)(1 mole Na/22.99 grams) = 223 moles of sodium =================
nothing
To find the number of moles in 1 kg of CF2Cl2, you first need to calculate the molar mass of CF2Cl2. Carbon has a molar mass of 12.01 g/mol, fluorine has a molar mass of 19.00 g/mol, and chlorine has a molar mass of 35.45 g/mol. Adding these up gives a molar mass of 120.91 g/mol for CF2Cl2. Next, convert 1 kg to grams (1000 g). Finally, divide 1000 g by the molar mass of CF2Cl2 to find the number of moles in 1 kg of CF2Cl2.
The balanced chemical equation for the reaction between ethylene glycol and phthalic anhydride is: C6H4(CO)2O + 2 C2H6O2 → C6H4(CO2CH2CH2O)2 + 2 H2O From the equation, it can be seen that 2 moles of water are produced for every 1 mole of ethylene glycol reacting with 1 mole of phthalic anhydride.
0.33 mol/kg (apex)
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, there are 2 moles of glycerin dissolved in 1000 g of water, which is equivalent to 1 kg. Therefore, the molality is 2 mol / 1 kg = 2 mol/kg.
To find the molarity, we first need to convert the mass of water to moles. Since 1 kg of water is approximately 1000 moles, 3 kg of water is 3000 moles. Then, molarity is calculated by dividing the number of moles of solute (NaOH) by the volume of solution in liters. So, the molarity would be 6 moles / 3 L = 2 M.
4 mol over 0.800 kg
First, calculate the moles of cane sugar: 38.0 g / 342.3 g/mol = 0.111 moles. Then, calculate the molality using the formula: molality = moles of solute / kg of solvent. Since 175 g of water is equivalent to 0.175 kg, molality = 0.111 moles / 0.175 kg = 0.634 mol/kg.
atomic weight of carbon dioxide is 2 * 16 + 12 = 44 1 kg = 1000 g 1 kg of co2 has 1000/44 = 22.7 moles yeh i think that's wrong lol isn't it 3.37E25?
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
Depends on the molecule. Look in the periodic table at the atomic weights. This number is the grams per mole. Carbon for example has 12 grams in each mole.