(1kg C2H6O2 )(1000g/1kg)(1mol/62g) = 16.1 moles
1 kg = 1000 grams 1 gram = 0.001 kg
1 14 kg is approximately 3.08 lbs.
1 kg = 1000 g
1000g is 1kg.
1 kg = 1000 g1 kg = 1000 g1 kg = 1000 g1 kg = 1000 g1 kg = 1000 g1 kg = 1000 g
Quite a few! 5.13 kilograms sodium (1000 grams/1 kg)(1 mole Na/22.99 grams) = 223 moles of sodium =================
nothing
To find the number of moles in 1 kg of CF2Cl2, you first need to calculate the molar mass of CF2Cl2. Carbon has a molar mass of 12.01 g/mol, fluorine has a molar mass of 19.00 g/mol, and chlorine has a molar mass of 35.45 g/mol. Adding these up gives a molar mass of 120.91 g/mol for CF2Cl2. Next, convert 1 kg to grams (1000 g). Finally, divide 1000 g by the molar mass of CF2Cl2 to find the number of moles in 1 kg of CF2Cl2.
The balanced chemical equation for the reaction between ethylene glycol and phthalic anhydride is: C6H4(CO)2O + 2 C2H6O2 → C6H4(CO2CH2CH2O)2 + 2 H2O From the equation, it can be seen that 2 moles of water are produced for every 1 mole of ethylene glycol reacting with 1 mole of phthalic anhydride.
0.33 mol/kg (apex)
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, there are 2 moles of glycerin dissolved in 1000 g of water, which is equivalent to 1 kg. Therefore, the molality is 2 mol / 1 kg = 2 mol/kg.
4 mol over 0.800 kg
To find the molarity, we first need to convert the mass of water to moles. Since 1 kg of water is approximately 1000 moles, 3 kg of water is 3000 moles. Then, molarity is calculated by dividing the number of moles of solute (NaOH) by the volume of solution in liters. So, the molarity would be 6 moles / 3 L = 2 M.
First, calculate the moles of cane sugar: 38.0 g / 342.3 g/mol = 0.111 moles. Then, calculate the molality using the formula: molality = moles of solute / kg of solvent. Since 175 g of water is equivalent to 0.175 kg, molality = 0.111 moles / 0.175 kg = 0.634 mol/kg.
atomic weight of carbon dioxide is 2 * 16 + 12 = 44 1 kg = 1000 g 1 kg of co2 has 1000/44 = 22.7 moles yeh i think that's wrong lol isn't it 3.37E25?
Molality (m) is defined as the number of moles of solute per kilogram of solvent. In this case, you have 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality of the solution is calculated as follows: ( m = \frac{2 \text{ moles}}{6 \text{ kg}} = \frac{1}{3} ) or approximately 0.33 mol/kg.
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).