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What is the molality of a solution that contains 2 moles of glycerin and dissolved in 1000 g of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, there are 2 moles of glycerin dissolved in 1000 g of water, which is equivalent to 1 kg. Therefore, the molality is 2 mol / 1 kg = 2 mol/kg.
What is the molarlity of a colution made by dissolving 6 moles of NaOH in 3 kg of water?
To find the molarity, we first need to convert the mass of water to moles. Since 1 kg of water is approximately 1000 moles, 3 kg of water is 3000 moles. Then, molarity is calculated by dividing the number of moles of solute (NaOH) by the volume of solution in liters. So, the molarity would be 6 moles / 3 L = 2 M.
How many the mole of CO 2 contains?
atomic weight of carbon dioxide is 2 * 16 + 12 = 44 1 kg = 1000 g 1 kg of co2 has 1000/44 = 22.7 moles yeh i think that's wrong lol isn't it 3.37E25?
What is the molality of a solution 2 moles of NaOH in 6 kg of water?
Molality (m) is defined as the number of moles of solute per kilogram of solvent. In this case, you have 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality of the solution is calculated as follows: ( m = \frac{2 \text{ moles}}{6 \text{ kg}} = \frac{1}{3} ) or approximately 0.33 mol/kg.
How many moles of KF are contained in 347 g of water in a 0.175 m KF solution?
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
How many moles are in 1 kg of C2H6O2?
To find the number of moles in 1 kg of C2H6O2, we first need to calculate the molar mass of C2H6O2: (212.01) + (61.01) + (2*16.00) = 62.07 g/mol. Then, we convert 1 kg to grams: 1 kg = 1000 g. Finally, we divide the mass by the molar mass to find the number of moles: 1000 g / 62.07 g/mol = 16.12 moles.
How many moles of sodium are in 5.13 kg of sodium?
Quite a few! 5.13 kilograms sodium (1000 grams/1 kg)(1 mole Na/22.99 grams) = 223 moles of sodium =================
Calculate with clear arrangements how many moles of oxygen are needed to burn 1 kg of ethane and 1 kg of ethanol, respectively?
nothing
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
0.33 mol/kg (apex)
What is the molality of a solution that contains 2 moles of glycerin and dissolved in 1000 g of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, there are 2 moles of glycerin dissolved in 1000 g of water, which is equivalent to 1 kg. Therefore, the molality is 2 mol / 1 kg = 2 mol/kg.
What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?
4 mol over 0.800 kg
What is the molarlity of a colution made by dissolving 6 moles of NaOH in 3 kg of water?
To find the molarity, we first need to convert the mass of water to moles. Since 1 kg of water is approximately 1000 moles, 3 kg of water is 3000 moles. Then, molarity is calculated by dividing the number of moles of solute (NaOH) by the volume of solution in liters. So, the molarity would be 6 moles / 3 L = 2 M.
What is the molality of a solution composed of 38.0 g of cane sugar (C12H 22O11) dissolved in 175 g of water?
First, calculate the moles of cane sugar: 38.0 g / 342.3 g/mol = 0.111 moles. Then, calculate the molality using the formula: molality = moles of solute / kg of solvent. Since 175 g of water is equivalent to 0.175 kg, molality = 0.111 moles / 0.175 kg = 0.634 mol/kg.
How many the mole of CO 2 contains?
atomic weight of carbon dioxide is 2 * 16 + 12 = 44 1 kg = 1000 g 1 kg of co2 has 1000/44 = 22.7 moles yeh i think that's wrong lol isn't it 3.37E25?
What is the molality of a solution 2 moles of NaOH in 6 kg of water?
Molality (m) is defined as the number of moles of solute per kilogram of solvent. In this case, you have 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality of the solution is calculated as follows: ( m = \frac{2 \text{ moles}}{6 \text{ kg}} = \frac{1}{3} ) or approximately 0.33 mol/kg.
How many moles of KF are contained in 347 g of water in a 0.175 m KF solution?
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
What is the molality of a solution made by a dissolving 2 moles of naoh in 6 kg of water Apex?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). In this case, with 2 moles of NaOH dissolved in 6 kg of water, the molality is ( m = \frac{2 , \text{moles}}{6 , \text{kg}} = \frac{1}{3} , \text{mol/kg} ). Therefore, the molality of the solution is approximately 0.33 mol/kg.
