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How many moles are there in 9g of Al show working?
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
How can balenced equations be used to calculate the volume of gases formed in chemical reactions?
The coefficients in a balanced chemical equation shows how many moles of each reactant is needed in order for a reaction to take place. After determining how many moles of each reactant is required, you would convert it to grams to calculate how much of each reactant is needed to form a given amount of product in a chemical reaction.
How many Na atoms are in 0.25 moles of Na Show work?
0.25 x 6.022 x 10^23=1.05055 x10^23
Please show work How many moles would there be in 300 ml of of a 1.5 M solution?
To find the number of moles, use the formula: moles = Molarity (M) x Volume (L). First, convert 300 ml to liters by dividing by 1000: 300 ml / 1000 = 0.3 L. Then, calculate moles = 1.5 M x 0.3 L = 0.45 moles. Therefore, there would be 0.45 moles in 300 ml of a 1.5 M solution.
Please show work How many moles would there be in 115 ml of a 0.652 M solution?
To find the number of moles in the solution, first convert the volume provided to liters (115 mL = 0.115 L). Then, multiply the volume in liters by the molarity of the solution: 0.115 L x 0.652 mol/L = 0.075 moles. So, there would be 0.075 moles in 115 mL of a 0.652 M solution.
How many moles are there in 9g of Al show working?
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
Help with stoichiometry show steps How many grams of KClO3 must be decomposed to yield 30 grams of oxygen?
2 KClO3 -> KCL + 3O2 Molar weight of O2 = 32 grams/mole (so close it doesn't matter) 30 grams/32grams/mole = 0.9375 moles Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?) now if we have 3 moles of O2 then we have 2 moles of KCl. If we have one mole of O2 then we have 2/3 moles of KCL What ever moles we have of O2 we must multiply it by 2/3 to get the moles of KCl So we have 0.9375moles of O2 x 2/3 = 0.625 moles of KCl So 0.625 moles of KCl x 74.5 grams/mole KCl = 46.5625 grams KCl
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
Can you show me how to calculate the of moles in 0.037g H2O This is the mass of water lost after heating.?
.037g x 1 mole of H2O / 18.02g H2O= .00205 moles H20 this is a simple factor label problem in which you multiply the number of grams by the number of grams per mole. Thus, the GRAMS cancel and you are left with moles. 18.02 is the molecular weight of H2O; 1.01+1.01+16= 18.02 g/mol
How many grams of aluminum are in 0.471 moles of aluminum please show your work?
The molar weight of aluminum (Al) is 26.98 g/mol. grams of Al = 26.98 x 0.471 = 12.71 g The molar weight of aluminum (Al) is 26.98 g/mol. grams of Al = 26.98 x 0.471 = 12.71 g The molar weight of aluminum (Al) is 26.98 g/mol. grams of Al = 26.98 x 0.471 = 12.71 g
How many grams does a quarter weight?
Most digital scales will not show a number that low ( I tried 3 )
In the formula for sodium phosphate Na3PO4 how many moles of sodium are represented?
There are 3 moles of sodium represented in one mole of sodium phosphate (Na3PO4). This is because the subscript 3 in Na3PO4 indicates that there are 3 sodium ions for every molecule of sodium phosphate.
How can balenced equations be used to calculate the volume of gases formed in chemical reactions?
The coefficients in a balanced chemical equation shows how many moles of each reactant is needed in order for a reaction to take place. After determining how many moles of each reactant is required, you would convert it to grams to calculate how much of each reactant is needed to form a given amount of product in a chemical reaction.
How would you find the grams on the periodic table?
The periodic table doesn't show grams; and which grams ?
How many Na atoms are in 0.25 moles of Na Show work?
0.25 x 6.022 x 10^23=1.05055 x10^23
What information in a balanced chemical equation shows how many moles of a reactant are involved in the reaction?
The coefficient (not a subscript or superscript) placed immediately before the formula of the reactant in the equation shows how many moles of a reactant are involved in the reaction. If there is no explicit coefficient, a value of 1 for the coefficient is assumed. The coefficient in front of the molecule tells its relative number of moles.
How many grams in a half kilogram show weighing scale to solve this problem?
This browser is too poor to show weighing scales. Therefore the question cannot be answered.
