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Help with stoichiometry show steps How many grams of KClO3 must be decomposed to yield 30 grams of oxygen?
2 KClO3 -> KCL + 3O2
Molar weight of O2 = 32 grams/mole (so close it doesn't matter)
30 grams/32grams/mole = 0.9375 moles
Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?)
now if we have 3 moles of O2 then we have 2 moles of KCl.
If we have one mole of O2 then we have 2/3 moles of KCL
What ever moles we have of O2 we must multiply it by 2/3 to get the moles of KCl
So we have 0.9375moles of O2 x 2/3 = 0.625 moles of KCl
So 0.625 moles of KCl x 74.5 grams/mole KCl = 46.5625 grams KCl
What else can I help you with?
When 46.0 g KClO3 is heated 12.1 g O2 is formed how many grams of KCl is also formed?
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
How many moles of KClO3 on decomposition give 1 mole of oxygen?
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
Oh, dude, chemistry time! So, when 25 grams of potassium chlorate decompose, you get 74.55% potassium chloride and 25.45% oxygen. So, if you do the math, you'd get around 18.64 grams of potassium chloride. But hey, who's counting, right?
What is the grams of substance in 2 moles of KClO3?
Alls you do to find a molar mass is add up all of the atomic masses. Potassium=39.09 Chlorine= 35.453 Oxygen(3)=15.999. So KClO3 would equal 271.65g to a mol? Then I think to find the number of atoms of each you would take the atomic mass * avacodo's number so it would be for example chlorine. 1gCl(35.453/1)(6.022*10^23/1) However I might be wrong on that part.
What mass of potassium chlorate would contain 40.0g of oxygen?
To calculate the mass of potassium chlorate containing 40.0g of oxygen, first determine the molar mass of oxygen (16g/mol). Then, use the molecular formula of potassium chlorate (KClO3) to find the oxygen's molar ratio in KClO3 (1:3). Finally, calculate the mass of KClO3 using the molar mass and the molar ratio to find that approximately 186 grams of potassium chlorate contain 40.0g of oxygen.
When 46.0 g KClO3 is heated 12.1 g O2 is formed how many grams of KCl is also formed?
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
How many moles of KClO3 on decomposition give 1 mole of oxygen?
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
Oh, dude, chemistry time! So, when 25 grams of potassium chlorate decompose, you get 74.55% potassium chloride and 25.45% oxygen. So, if you do the math, you'd get around 18.64 grams of potassium chloride. But hey, who's counting, right?
What is the grams of substance in 2 moles of KClO3?
Alls you do to find a molar mass is add up all of the atomic masses. Potassium=39.09 Chlorine= 35.453 Oxygen(3)=15.999. So KClO3 would equal 271.65g to a mol? Then I think to find the number of atoms of each you would take the atomic mass * avacodo's number so it would be for example chlorine. 1gCl(35.453/1)(6.022*10^23/1) However I might be wrong on that part.
What mass of potassium chlorate would contain 40.0g of oxygen?
To calculate the mass of potassium chlorate containing 40.0g of oxygen, first determine the molar mass of oxygen (16g/mol). Then, use the molecular formula of potassium chlorate (KClO3) to find the oxygen's molar ratio in KClO3 (1:3). Finally, calculate the mass of KClO3 using the molar mass and the molar ratio to find that approximately 186 grams of potassium chlorate contain 40.0g of oxygen.
How many grams of potassium chlorate decomposes to yield 30 grams of oxygen?
The molar mass of potassium chlorate (KClO3) is 122.55 g/mol. This means that 122.55 grams of potassium chlorate yield 3 moles of oxygen gas. To calculate the amount of potassium chlorate that decomposes to yield 30 grams of oxygen, you can set up a simple ratio using the molar masses.
Why is 160 grams of oxygen mass would be produced?
This question seems to be about the reactant side of a chemical equation. To calculate the mass of oxygen produced, you need to know the stoichiometry of the reaction. Without that information, it is not possible to determine why 160 grams of oxygen would be produced.
How many grams of oxygen are produced in the decomposition of 6.02g of potassium chlorate?
The decomposition of potassium chlorate produces oxygen gas and potassium chloride. The molar ratio of oxygen to potassium chlorate is 3:2. Therefore, to find the grams of oxygen produced, you would calculate (6.02g * 3 mol O2/2 mol KClO3) * molar mass of O2.
When the amount of oxygen is limited carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
Water decomposes to make 4 gram hydrogen gas and 32 g of oxygen gas what mass of water is decomposed?
To find the mass of water decomposed, we first need to calculate the total mass of the products formed, which is 4g (hydrogen gas) + 32g (oxygen gas) = 36g. The original mass of water decomposed is equal to the total mass of products formed, so 36g of water is decomposed.
How many grams of gas are needed to react with 348.5 grams of oxygen?
To determine the amount of gas needed to react with 348.5 grams of oxygen, you need to know the balanced chemical equation of the reaction. Then, use the stoichiometry of the reaction to calculate the amount of gas required based on the molar ratio between the gas and oxygen in the reaction.
How many grams of oxygen are needed to react with 6.78 grams of ammonia?
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
