Oh, dude, chemistry time! So, when 25 grams of potassium chlorate decompose, you get 74.55% potassium chloride and 25.45% oxygen. So, if you do the math, you'd get around 18.64 grams of potassium chloride. But hey, who's counting, right?
The reaction between potassium chlorate and oxygen gas generates potassium chloride and oxygen gas. Therefore, the amount of potassium chlorate produced from the reaction is equal to the amount of potassium chlorate that was used, which is 500 grams.
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
The decomposition of potassium chlorate produces oxygen gas and potassium chloride. The molar ratio of oxygen to potassium chlorate is 3:2. Therefore, to find the grams of oxygen produced, you would calculate (6.02g * 3 mol O2/2 mol KClO3) * molar mass of O2.
Potassium chlorate is a chemical compound composed of potassium, chlorine, and oxygen. It is not typically found in nature in its pure form but can be produced synthetically for various industrial uses, such as in fireworks, matches, and explosives.
The balanced chemical equation for the decomposition of potassium chlorate (KClO3) into oxygen (O2) and potassium chloride (KCl) is 2KClO3 -> 2KCl + 3O2. This means that for every 2 moles of KClO3, 2 moles of KCl and 3 moles of O2 are produced.
The reaction between potassium chlorate and oxygen gas generates potassium chloride and oxygen gas. Therefore, the amount of potassium chlorate produced from the reaction is equal to the amount of potassium chlorate that was used, which is 500 grams.
I Don't knows Sorry
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
The decomposition of potassium chlorate produces oxygen gas and potassium chloride. The molar ratio of oxygen to potassium chlorate is 3:2. Therefore, to find the grams of oxygen produced, you would calculate (6.02g * 3 mol O2/2 mol KClO3) * molar mass of O2.
Potassium chlorate is a chemical compound composed of potassium, chlorine, and oxygen. It is not typically found in nature in its pure form but can be produced synthetically for various industrial uses, such as in fireworks, matches, and explosives.
The balanced chemical equation for the decomposition of potassium chlorate (KClO3) into oxygen (O2) and potassium chloride (KCl) is 2KClO3 -> 2KCl + 3O2. This means that for every 2 moles of KClO3, 2 moles of KCl and 3 moles of O2 are produced.
There is a good method posted on: http://www.skepticfiles.org/new/003doc.htm (just read up to "Powder these to the consistency of face powder, and heat gently to drive off all moisture.") This basically describes taking bleach heating it, adding potassium chloride (easy-to-buy salt substitute), cooling the solution, and filtering it. Heating the bleach causes the NaClO (sodium hypochlorite) to decompose into NaCl (table salt) and NaClO3 (sodium chlorate). Upon the addition of the KCl (potassium chloride), the NaClO3 and KCl undergo and double displacement reaction creating the KClO3. 3NaClO ---> 2NaCl + NaClO3 NaClO3 + KCl ---> KClO3 + NaCl The method was easy and successful for me, but if worst comes to worst, do a Google search and it will point you in the right direction. Disclaimer: This is for educational purposes and this answer is not liable for any damages to you, due to attempting this process.
For every mole of potassium chlorate that decomposes, three moles of oxygen are produced. Therefore, if 7.5 moles of potassium chlorate decompose, 22.5 moles of oxygen would be produced (7.5 moles x 3).
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
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To calculate the amount of oxygen gas produced from potassium chlorate, use the balanced chemical equation for the decomposition of potassium chlorate: 2KClO3 -> 2KCl + 3O2. From the equation, every 2 moles of KClO3 produce 3 moles of O2. First, convert the given mass of KClO3 to moles, then use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, convert moles of O2 to grams using its molar mass (32 g/mol).
No, reacting zinc with hydrogen chloride will yield zinc chloride and hydrogen gas. Potassium chloride can be prepared by reacting potassium with hydrogen chloride or (more safely) potassium hydroxide with hydrogen chloride.