Oh, dude, you're hitting me with that chemistry question! So, like, one mole of any element contains Avogadro's number of atoms, which is 6.022 x 10^23. In this case, you've got 4.5 moles of Li, so you just multiply that by Avogadro's number to get the total number of Li atoms. That's like... a lot of Li atoms, man.
3,00 moles of Li have 18,066422571.10e23 atoms.
4.7 mole Li (6.022 X 10^23/1 mole Li) = 2.8 X 10^24 atoms Li
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
Well, honey, if we're talking about lithium (Li) and you've got 55.2 grams of it, you're looking at approximately 7.4 x 10^23 atoms. That's a whole lotta Li atoms in your hands. Hope you've got a plan for all that atomic power!
3,00 moles of Li have 18,066422571.10e23 atoms.
How many lithium atoms are in 10.56 g of lithium
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
4.7 mole Li (6.022 X 10^23/1 mole Li) = 2.8 X 10^24 atoms Li
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
1 mole of Li₂O contains 2 moles of lithium (Li) atoms and 1 mole of oxygen (O) atoms. Therefore, in 1 mole of Li₂O, there are a total of 3 moles of atoms.
No moles of BaCO3 are found in any amount of Li.
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
For this problem, the atomic mass is not required. Take the mass in moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for the units to cancel.2.5 moles H2 × (6.02 × 1023 atoms) = 1.51 × 1024 atoms
Well, honey, if we're talking about lithium (Li) and you've got 55.2 grams of it, you're looking at approximately 7.4 x 10^23 atoms. That's a whole lotta Li atoms in your hands. Hope you've got a plan for all that atomic power!
3.977 mol
Remember the Avogadro Number. 1 moles = 6.022 x 10^(23) atoms/molecules. So for 0.106 moles lithium it is 0.106 X 6.022 x 10^(23) = 6.38 x 10^(22) atoms (Li). or stringing it out 6,380,000,000,000,000,000,000 atoms