3.977 mol
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
To find the mass of 21.3 moles of lithium (Li), you can use the molar mass of lithium, which is approximately 6.94 g/mol. Multiply the number of moles by the molar mass: (21.3 , \text{mol} \times 6.94 , \text{g/mol} = 147.58 , \text{g}). Therefore, the mass of 21.3 moles of lithium is approximately 147.58 grams.
The balanced chemical equation for the formation of lithium nitride (Li3N) from lithium and nitrogen is: [ 6 \text{Li} + \text{N}_2 \rightarrow 2 \text{Li}_3\text{N} ] From the equation, 6 moles of lithium produce 2 moles of Li3N. Therefore, to produce 0.31 moles of Li3N, you would need ( 0.31 \text{ mol Li3N} \times \frac{6 \text{ mol Li}}{2 \text{ mol Li3N}} = 0.93 \text{ mol Li} ). Thus, 0.93 moles of lithium are required.
Lithium's atomic symbol is Li. It's atomic number is 3, and it's relative atomic mass (Ar) is 6.9 Lithium is in Group 1 and is highly reactant, most likely to give an electron when forming a compound
20,32 g of lithium nitride can be obtained.
How many lithium atoms are in 10.56 g of lithium
From the periodic table, lithium has an atomic weight of 6.941. The molar mass of an element is the atomic weight in grams. Therefore, 1 mole Li = 6.941g Li Therefore, moles Li = 15g Li X 1 mole Li/6.941g Li = 2.2 moles Li
To calculate the number of lithium (Li) atoms in 6.6 moles, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiply the number of moles by Avogadro's number: [6.6 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 3.97 \times 10^{24} , \text{Li atoms}.] Thus, there are approximately (3.97 \times 10^{24}) lithium atoms in 6.6 moles of Li.
To find the number of moles of lithium in 27.6 g, you first need to determine the molar mass of lithium, which is approximately 6.94 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 27.6 g ÷ 6.94 g/mol ≈ 3.98 moles of lithium.
3,00 moles of Li have 18,066422571.10e23 atoms.
This reaction? 6Li + N2 --> 2Li3N 0.450 moles Li (2 moles Li3N/6 moles Li) = 0.150 moles lithium nitride produced ===========================
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
To find the mass of 21.3 moles of lithium (Li), you can use the molar mass of lithium, which is approximately 6.94 g/mol. Multiply the number of moles by the molar mass: (21.3 , \text{mol} \times 6.94 , \text{g/mol} = 147.58 , \text{g}). Therefore, the mass of 21.3 moles of lithium is approximately 147.58 grams.
15g Li * (1mol Li / 6.941g Li) = 2.16 mol Li
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.