3.977 mol
From the periodic table, lithium has an atomic weight of 6.941. The molar mass of an element is the atomic weight in grams. Therefore, 1 mole Li = 6.941g Li Therefore, moles Li = 15g Li X 1 mole Li/6.941g Li = 2.2 moles Li
3,00 moles of Li have 18,066422571.10e23 atoms.
This reaction? 6Li + N2 --> 2Li3N 0.450 moles Li (2 moles Li3N/6 moles Li) = 0.150 moles lithium nitride produced ===========================
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
3.977 mol
How many lithium atoms are in 10.56 g of lithium
From the periodic table, lithium has an atomic weight of 6.941. The molar mass of an element is the atomic weight in grams. Therefore, 1 mole Li = 6.941g Li Therefore, moles Li = 15g Li X 1 mole Li/6.941g Li = 2.2 moles Li
To calculate the number of lithium (Li) atoms in 6.6 moles, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiply the number of moles by Avogadro's number: [6.6 , \text{moles} \times 6.022 \times 10^{23} , \text{atoms/mole} \approx 3.97 \times 10^{24} , \text{Li atoms}.] Thus, there are approximately (3.97 \times 10^{24}) lithium atoms in 6.6 moles of Li.
3,00 moles of Li have 18,066422571.10e23 atoms.
This reaction? 6Li + N2 --> 2Li3N 0.450 moles Li (2 moles Li3N/6 moles Li) = 0.150 moles lithium nitride produced ===========================
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
To find the mass of 21.3 moles of lithium (Li), you can use the molar mass of lithium, which is approximately 6.94 g/mol. Multiply the number of moles by the molar mass: (21.3 , \text{mol} \times 6.94 , \text{g/mol} = 147.58 , \text{g}). Therefore, the mass of 21.3 moles of lithium is approximately 147.58 grams.
15g Li * (1mol Li / 6.941g Li) = 2.16 mol Li
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.