3.977 mol
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
For an element such as lithium, the technically correct term is "gram atomic mass" instead of "mole", and for lithium, the gram atomic mass is about 6.941. Therefore, the answer to the question is (5.48)(6.941) or 37.5 grams, to the justified number of significant digits.
How many lithium atoms are in 10.56 g of lithium
The gram Atomic Mass of lithium is 6.941; this is the amount of lithium that contains Avogadro's Number of atoms. Therefore, in 18.7 g of lithium, there will be (18.7)/(6.941) times Avogadro's Number of atoms, or about 1.62 X 1024, to the justified number of significant digits.
To find the number of moles in 51 grams of lithium phosphate, you first need to determine its molar mass. The molar mass of lithium phosphate (Li3PO4) is 115.79 g/mol. To find the number of moles, divide the given mass by the molar mass: 51 g / 115.79 g/mol ≈ 0.44 moles of lithium phosphate.
To find the number of moles of lithium in 27.6 g, you first need to determine the molar mass of lithium, which is approximately 6.94 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 27.6 g ÷ 6.94 g/mol ≈ 3.98 moles of lithium.
To find the number of moles in 1.9 g of lithium, you need to divide the mass of lithium by its molar mass. The molar mass of lithium is approximately 6.94 g/mol. So, 1.9 g / 6.94 g/mol ≈ 0.274 moles of lithium.
The molar mass of lithium is approximately 6.94 g/mol. To find the mass of 5.40 moles of lithium, multiply the number of moles by the molar mass: 5.40 moles * 6.94 g/mol = 37.476 g. So, the mass of 5.40 moles of lithium is 37.476 grams.
3.977 mol
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
To convert grams of lithium to moles, we need to divide the mass of lithium by its molar mass. The molar mass of lithium is approximately 6.94 g/mol. Moles = 318.0 g / 6.94 g/mol = 45.82 moles. Therefore, 318.0 grams of lithium is equivalent to 45.82 moles.
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
0.0000639mol
For an element such as lithium, the technically correct term is "gram atomic mass" instead of "mole", and for lithium, the gram atomic mass is about 6.941. Therefore, the answer to the question is (5.48)(6.941) or 37.5 grams, to the justified number of significant digits.
To convert moles of lithium to grams, you need to multiply the number of moles by the molar mass of lithium. The molar mass of lithium is 6.94 g/mol. Therefore, 0.0295 mol of lithium is equal to 0.0295 mol * 6.94 g/mol = 0.2053 grams.
How many lithium atoms are in 10.56 g of lithium