Multiply by molar mass.0.0295*6.9412=0.2048g
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
To convert grams of lithium to moles, we need to divide the mass of lithium by its molar mass. The molar mass of lithium is approximately 6.94 g/mol. Moles = 318.0 g / 6.94 g/mol = 45.82 moles. Therefore, 318.0 grams of lithium is equivalent to 45.82 moles.
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
To convert grams of lithium to moles, we need to divide the mass of lithium by its molar mass. The molar mass of lithium is approximately 6.94 g/mol. Moles = 318.0 g / 6.94 g/mol = 45.82 moles. Therefore, 318.0 grams of lithium is equivalent to 45.82 moles.
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
To calculate the grams of lithium bromide present in the solution, you would first determine the moles of lithium bromide using the formula: moles = Molarity x Volume (L). Once you have the moles, you can convert it to grams using the molar mass of lithium bromide (86.85 g/mol).
2.32
Lithium's molar mass is 6.941g/mol. To find the molar mass of an element, take the atomic weight on the periodic table in grams.
5.0 mol Li * 6.941 g/mol Li = 34.705 = 35 g Lithium
The molar mass of lithium is approximately 6.94 g/mol. To find the mass of 5.40 moles of lithium, multiply the number of moles by the molar mass: 5.40 moles * 6.94 g/mol = 37.476 g. So, the mass of 5.40 moles of lithium is 37.476 grams.
To determine the grams in 4.500 Li2O (lithium oxide), you need to calculate the molar mass of Li2O. Lithium has a molar mass of approximately 6.94 g/mol and oxygen has a molar mass of approximately 16.00 g/mol. Therefore, the molar mass of Li2O is 14.94 g/mol. To find the grams in 4.500 Li2O, multiply the molar mass by the amount given (4.5 mol * 14.94 g/mol).
For an element such as lithium, the technically correct term is "gram atomic mass" instead of "mole", and for lithium, the gram atomic mass is about 6.941. Therefore, the answer to the question is (5.48)(6.941) or 37.5 grams, to the justified number of significant digits.