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318.0 grams of lithium in moles?
To convert grams of lithium to moles, we need to divide the mass of lithium by its molar mass. The molar mass of lithium is approximately 6.94 g/mol. Moles = 318.0 g / 6.94 g/mol = 45.82 moles. Therefore, 318.0 grams of lithium is equivalent to 45.82 moles.
How many grams are in 0.0864 moles of lithium?
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
What is the mass in grams of 5.40 moles of lithium?
The molar mass of lithium is approximately 6.94 g/mol. To find the mass of 5.40 moles of lithium, multiply the number of moles by the molar mass: 5.40 moles * 6.94 g/mol = 37.476 g. So, the mass of 5.40 moles of lithium is 37.476 grams.
What is the number of moles of 27.6 g of lithium Li?
To find the number of moles of lithium in 27.6 g, you first need to determine the molar mass of lithium, which is approximately 6.94 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 27.6 g ÷ 6.94 g/mol ≈ 3.98 moles of lithium.
How many grams are in 3 moles of lithium?
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
318.0 grams of lithium in moles?
To convert grams of lithium to moles, we need to divide the mass of lithium by its molar mass. The molar mass of lithium is approximately 6.94 g/mol. Moles = 318.0 g / 6.94 g/mol = 45.82 moles. Therefore, 318.0 grams of lithium is equivalent to 45.82 moles.
How many grams are in 0.0864 moles of lithium?
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
What is the mass in grams of 5.40 moles of lithium?
The molar mass of lithium is approximately 6.94 g/mol. To find the mass of 5.40 moles of lithium, multiply the number of moles by the molar mass: 5.40 moles * 6.94 g/mol = 37.476 g. So, the mass of 5.40 moles of lithium is 37.476 grams.
What is the number of moles of 27.6 g of lithium Li?
To find the number of moles of lithium in 27.6 g, you first need to determine the molar mass of lithium, which is approximately 6.94 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 27.6 g ÷ 6.94 g/mol ≈ 3.98 moles of lithium.
How much lithium is in 0.000444 g of lithium answer in units of moles?
0.0000639mol
How many grams are in 3 moles of lithium?
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
How many moles of Li atoms are in 10.56grams of Li?
How many lithium atoms are in 10.56 g of lithium
How many atoms of lithium are in 11.8 g?
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
How many grams of Li3N can be formed from 1.75 moles of Li?
20,32 g of lithium nitride can be obtained.
A student weighed 0.550 grams of lithium chloride LiCl to use in a reaction How many moles is this?
To find the number of moles in 0.550 grams of LiCl, divide the mass by the molar mass of LiCl, which is approximately 42.4 g/mol. 0.550 g LiCl / 42.4 g/mol LiCl ≈ 0.013 mol LiCl. Therefore, the student has approximately 0.013 moles of LiCl.
How much would 5.0 moles of lithium weigh in gram?
5.0 mol Li * 6.941 g/mol Li = 34.705 = 35 g Lithium
What is the mass grams of 5.40 moles of lithium?
For an element such as lithium, the technically correct term is "gram atomic mass" instead of "mole", and for lithium, the gram atomic mass is about 6.941. Therefore, the answer to the question is (5.48)(6.941) or 37.5 grams, to the justified number of significant digits.
