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how many moles in 0.550 g of lithium

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Q: A student weighed 0.550 grams of lithium chloride LiCl to use in a reaction How many moles is this?
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A student weighed 0.550 g of lithium chloride LiCl to use in a reaction How many moles is this?

Remember the equation # moles = mass(g) / Mr ( Relative molcular mass) The Mr of LiCl is: - 1 x Li = 1 x 7 = 7 1 x Cl = 1 x 35.5 = 35.5 7 + 35.5 = 42.5 Substituting moles(LiCl) = 0.55 g/ 42.5 = 0.0129... ~ 0.013


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