I assume you mean;
0.01456 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li)
= 1.263 X 10^21 atoms of lithium
In a formula unit of lithium phosphate, the chemical formula is Li3PO4. This means there are 4 oxygen atoms present (1 phosphorus atom and 4 oxygen atoms).
There are 3 atoms in lithium oxide. It consists of one lithium atom and two oxygen atoms.
Lithium phosphate has the chemical formula Li3PO4, which means it contains 3 lithium atoms, 1 phosphorus atom, and 4 oxygen atoms. In total, there are 8 atoms in lithium phosphate.
There are 16 atoms in lithium chlorate (LiClO3). This includes one lithium atom, one chlorine atom, and three oxygen atoms.
Lithium carbonate (Li2CO3) contains 6 atoms: 2 lithium (Li) atoms, 1 carbon (C) atom, and 3 oxygen (O) atoms.
In a formula unit of lithium phosphate, the chemical formula is Li3PO4. This means there are 4 oxygen atoms present (1 phosphorus atom and 4 oxygen atoms).
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
There are 3 atoms in lithium oxide. It consists of one lithium atom and two oxygen atoms.
Lithium Sulfate Li2SO4 has 4 oxygen atoms per molecule.
Lithium phosphate has the chemical formula Li3PO4, which means it contains 3 lithium atoms, 1 phosphorus atom, and 4 oxygen atoms. In total, there are 8 atoms in lithium phosphate.
There are 16 atoms in lithium chlorate (LiClO3). This includes one lithium atom, one chlorine atom, and three oxygen atoms.
Lithium carbonate (Li2CO3) contains 6 atoms: 2 lithium (Li) atoms, 1 carbon (C) atom, and 3 oxygen (O) atoms.
All lithium atoms (ions or neutral) have 3 protons.
Two atoms of lithium will combine with three atoms of oxygen to form lithium oxide, with the chemical formula Li2O. Each lithium atom can donate one electron to each oxygen atom, resulting in a stable compound.
4.8184X1023
The gram Atomic Mass of lithium is 6.941; this is the amount of lithium that contains Avogadro's Number of atoms. Therefore, in 18.7 g of lithium, there will be (18.7)/(6.941) times Avogadro's Number of atoms, or about 1.62 X 1024, to the justified number of significant digits.
Li is lithium. Never heard of Ci.Do you mean Cl? That would be Lithium Chloride LiCl...