341 grams scandium (1 mole Sc/44.96 grams)(6.022 X 1023/1 mole Sc)
= 4.57 X 1024 atoms of scandium
=====================
Scandium sulfide ScS: 2 atomsScandium sulfide Sc2S3: 5 atoms
That depends on how much of the substance you have. Assuming you mean in one formula, the answer is 7.
1 Electronic configuration of scandium: [Ar]3d1.4s2.
The answer is 6,2729.10e+26 carbon atoms.
9 half lives have elapsed to yield a sample with 125 atoms of C-14 and 375 atoms of N-14.
Scandium sulfide ScS: 2 atomsScandium sulfide Sc2S3: 5 atoms
The gram atomic mass of scandium is 44.9559. From the definition of Avogadro's Number, one gram atomic mass of any element contains 6.022 X 1023 atoms of the element. 341/44.9559 constitutes about 7.585 gram atomic masses and therefore contains (7.585)(6.022 X 1023) or 4.57 X 1024 atoms of scandium, to the justified number of significant digits.
That depends on how much of the substance you have. Assuming you mean in one formula, the answer is 7.
341g = 12.03oz
1 Electronic configuration of scandium: [Ar]3d1.4s2.
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
The number of atoms is 1,50553521.10e23.
Approx. 9.1024 atoms.
1,600
The answer is 6,2729.10e+26 carbon atoms.
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
9 half lives have elapsed to yield a sample with 125 atoms of C-14 and 375 atoms of N-14.