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118.7 is close to the 118.96 grams per mole (mass) of tin. So we can call that one mole. 1 mole is equal to 6.022x10^23 (avogadro's number which is the number of atoms per mole of an element).

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How many atoms of tin are in 119 g of tin?

To find the number of atoms, divide the given mass (119 g) by the molar mass of tin (118.71 g/mol) to get the number of moles. Then, multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms.


How many moles of tin atoms are in a pure tin cup with a mass of 41.7 g?

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How many atoms of 124Sn are present in 12.0 g of naturally occurring tin?

To determine the number of atoms of 124Sn in 12.0 g of naturally occurring tin, you need to first calculate the moles of tin using its molar mass (118.71 g/mol). Then, since natural tin consists of about 5% of 124Sn isotope, you can determine the number of moles of 124Sn in the sample. Finally, use Avogadro's number (6.022 x 10^23) to find the number of atoms of 124Sn.


How many atoms are there in 40.2 g of tin (Sn)?

To find the number of atoms in 40.2 g of tin (Sn), first determine the molar mass of tin, which is approximately 118.71 g/mol. Then, calculate the number of moles in 40.2 g by dividing the mass by the molar mass: ( \frac{40.2 , \text{g}}{118.71 , \text{g/mol}} \approx 0.339 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number ((6.022 \times 10^{23} , \text{atoms/mol})) to find the total number of atoms: ( 0.339 , \text{mol} \times 6.022 \times 10^{23} \approx 2.04 \times 10^{23} , \text{atoms} ).


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To find the total amount of tin (Sn) in 1462 atoms, you would need to multiply the number of atoms by the atomic mass of tin (Sn), which is approximately 118.71 grams per mole. However, you also need to divide by Avogadro's number (6.022 x 10^23 atoms per mole) to convert from atoms to grams.


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