The number of atoms of lead is 6,68.10e23.
To determine the number of atoms in 0.230 g of lead (Pb), you first need to calculate the number of moles of Pb using its molar mass (207.2 g/mol). This can be done by dividing the given mass (0.230 g) by the molar mass of Pb. Next, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert the moles of Pb to atoms. Therefore, in 0.230 g of Pb, there are approximately 6.58 x 10^21 atoms.
To find the number of atoms in 0.23 g of lead (Pb), you first need to determine the number of moles using the molar mass of lead. Lead has a molar mass of approximately 207.2 g/mol. Then use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
how many moles are represented by 1.51 x 10^24 atoms Pb
To find the number of atoms in 45 grams of Pb (lead), we need to first calculate the number of moles. The molar mass of Pb is approximately 207.2 g/mol. By dividing the given mass by the molar mass, we can find the number of moles. Then, we can convert moles to atoms using Avogadro's number (6.022 x 10^23 atoms/mol).
There are 1.204 x 1023 atoms in .200 mol of Pb.
To find the number of moles, you need to divide the given mass (9.51 x 10^3 g) by the molar mass of Pb. The molar mass of lead (Pb) is approximately 207.2 g/mol. So, 9.51 x 10^3 g Pb is equivalent to about 45.9 moles of Pb.
9
there are 6.022 x 1023 atoms in 1 mole, so if you have 6.755 moles of Pb that would be be 6.755(6.022 x 1023) which is 4.067861 x 1024 atoms
There are a total of 29 atoms in 2 molecules of lead(II) nitrate [2 Pb(NO3)2]: 4 atoms of lead, 4 atoms of nitrogen, and 21 atoms of oxygen.
9
0.44 mole Pb (6.022 X 10^23/1 mole Pb) = 2.6 X 10^23 atoms of lead
The answer depends on the amount of the substance.