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To determine the number of atoms in 0.230 g of lead (Pb), you first need to calculate the number of moles of Pb using its molar mass (207.2 g/mol). This can be done by dividing the given mass (0.230 g) by the molar mass of Pb. Next, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert the moles of Pb to atoms. Therefore, in 0.230 g of Pb, there are approximately 6.58 x 10^21 atoms.
What else can I help you with?
How many moles are represented by 32.50 g Mg?
how many moles are represented by 1.51 x 10^24 atoms Pb
How many molecules is in 291.25g of Pb's?
291.25 grams of lead (1 mole Pb/207.2 grams)(6.022 X 10^23/1 mole Pb) = 8.4648 X 10^23 atoms of lead I think you meant to say atoms, not molecules, as that is not a molecular formula and looks a lot like the symbol for lead with a possessive mark and s.
Which one has a greater mass..2 atoms of lead or 0.000000000000000000000051 mole of helium?
207.2/ 6.022*10^23 = 34.4 x 10-23 g, mass of 1 Pb atom For two atoms: 34.4*2= 68.8 x 10-23 g Pb 5.1*10^-23*4.003 g He (atomic mass) / 1 mol He= 20.4*10^-23 g He And the mass of lead is greater.
Grams in 33.3 moles of lead?
The molar mass of lead (Pb) is approximately 207.2 g/mol. To find the mass of 33.3 moles of lead, you would multiply the number of moles by the molar mass: 33.3 moles * 207.2 g/mol = approximately 6890.76 grams of lead.
How many atoms of sulfur (S) are in 5 g of sulfur?
5 g of sulfur contain 0,94.10e23 atoms.
How many atoms are in g Pb?
The number of atoms of lead is 6,68.10e23.
How many atoms are in .23 g Pb?
To find the number of atoms in 0.23 g of lead (Pb), you first need to determine the number of moles using the molar mass of lead. Lead has a molar mass of approximately 207.2 g/mol. Then use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
How many moles are represented by 32.50 g Mg?
how many moles are represented by 1.51 x 10^24 atoms Pb
How many atoms are in 45 grams of pb?
To find the number of atoms in 45 grams of Pb (lead), we need to first calculate the number of moles. The molar mass of Pb is approximately 207.2 g/mol. By dividing the given mass by the molar mass, we can find the number of moles. Then, we can convert moles to atoms using Avogadro's number (6.022 x 10^23 atoms/mol).
How many moles of Pb are equivalent to 9.51 times 103 g Pb?
To find the number of moles, you need to divide the given mass (9.51 x 10^3 g) by the molar mass of Pb. The molar mass of lead (Pb) is approximately 207.2 g/mol. So, 9.51 x 10^3 g Pb is equivalent to about 45.9 moles of Pb.
How many atoms are in 6.755 mole Pb?
there are 6.022 x 1023 atoms in 1 mole, so if you have 6.755 moles of Pb that would be be 6.755(6.022 x 1023) which is 4.067861 x 1024 atoms
How many molecules is in 291.25g of Pb's?
291.25 grams of lead (1 mole Pb/207.2 grams)(6.022 X 10^23/1 mole Pb) = 8.4648 X 10^23 atoms of lead I think you meant to say atoms, not molecules, as that is not a molecular formula and looks a lot like the symbol for lead with a possessive mark and s.
What is the number of atoms in 103.6 grams of Pb?
Ready for a bit of dimensional analysis? What we know: 1 mole Pb=207.2g Pb The math part: 103.6gPb x (1molPh/207.2gPb) = 0.500molPb Notice I had 0.500, with two zeros. This is due to significant figures.
How many grams of Pb are formed when 0.105 g NH react?
None. When NH reacts there is no Pb involved and so there is none formed.
What is the mass of 6.25x1020 atoms of lead?
The molar mass of lead (Pb) is 207.2 g/mol. To find the mass of 6.25x10^20 atoms, you need to divide the number of atoms by Avogadro's number (6.022x10^23) to get the number of moles, then multiply by the molar mass of lead. The mass of 6.25x10^20 atoms of lead is approximately 1.72 grams.
Which one has a greater mass..2 atoms of lead or 0.000000000000000000000051 mole of helium?
207.2/ 6.022*10^23 = 34.4 x 10-23 g, mass of 1 Pb atom For two atoms: 34.4*2= 68.8 x 10-23 g Pb 5.1*10^-23*4.003 g He (atomic mass) / 1 mol He= 20.4*10^-23 g He And the mass of lead is greater.
Grams in 33.3 moles of lead?
The molar mass of lead (Pb) is approximately 207.2 g/mol. To find the mass of 33.3 moles of lead, you would multiply the number of moles by the molar mass: 33.3 moles * 207.2 g/mol = approximately 6890.76 grams of lead.
