The answer is 3.32*10^23 atoms
2.3 × 1024 atoms of Ar
To find the number of argon atoms in a 40.0-g sample, you first need to calculate the number of moles of argon in the sample using the molar mass of argon (39.95 g/mol). Then, you can use Avogadro's number (6.022x10^23 atoms/mol) to determine the number of atoms in that many moles of argon.
First, calculate the number of moles in the 40.0 g sample of argon: 40.0 g / 39.948 g/mol = 1.00 mol. Then, use Avogadro's constant (6.022 x 10^23 atoms/mol) to find the number of atoms in 1.00 mol of argon, which is 6.022 x 10^23 atoms.
To find the number of argon atoms in 1.5x10^2g of argon, we first need to determine the molar mass of argon. The molar mass of argon is approximately 39.95 g/mol. Next, we convert the given mass to moles by dividing by the molar mass. Finally, we use Avogadro's number (6.022x10^23) to convert moles to atoms. The number of argon atoms in 1.5x10^2g of argon would be approximately (1.5x10^2g / 39.95g/mol) x 6.022x10^23 atoms.
To find the number of argon atoms, we first need to determine the molar mass of argon: 39.95 g/mol. Next, we convert the given mass to moles using the molar mass: 1.5 x 10^2 g / 39.95 g/mol = 3.75 mol. Finally, we use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms: 3.75 mol x 6.022 x 10^23 atoms/mol ≈ 2.26 x 10^24 argon atoms.
We need:The atomic weight of Argon (Ar), which is 39.948. We will round to 39.9.Avocado's Number, we'll use 6.02 * 1023(40 g Ag) / (39.9 g/mol) * ( 6.02e23 atom/mol ) = 6.04 * 1023 atoms AgAlternatively, if you used 40 g as the atomic weight for Ar, you could just use Avocado's Number since (40 g / 40 g/mol = 1 mol )
To calculate the number of atoms in 35.4g of argon, you need to divide the given mass by the molar mass of argon to get the number of moles, and then multiply by Avogadro's number (6.022 x 10^23 atoms/mol). The molar mass of argon is approximately 39.95 g/mol. So, 35.4g / 39.95 g/mol = 0.887 moles of argon. Multiplying by Avogadro's number gives 0.887 mol x 6.022 x 10^23 atoms/mol ≈ 5.34 x 10^23 atoms.
2.17*10^22
At 0 °C, 101.325 kPa, the density is 1.784 g/L
The molar mass of arsenic is 74.92 g/mol, and the molar mass of argon is 39.95 g/mol. Since the same number of atoms is present in equal masses, you'd set up a ratio of their molar masses to find the mass of arsenic equivalent to 39.95 g of argon. This gives you (74.92 g/mol) / (39.95 g/mol) = 1.874. Therefore, the mass of arsenic equivalent to 39.95 g of argon is 1.874 x 39.95 g = 74.84 g.
Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.
There are 6.022 x 10^22 atoms of sulfur in 1 gram, which is equivalent to Avogadro's number for a single element sulfur.