2.17*10^22
To find the number of silver atoms in 3.88 g of silver, you can use the formula: Number of atoms = (mass in grams / molar mass) x Avogadro's number The molar mass of silver is 107.87 g/mol, and Avogadro's number is 6.022 x 10^23 mol^-1. Therefore, there are approximately 8.59 x 10^22 silver atoms in 3.88 g of silver.
To calculate the number of silver atoms in 3.68 g of silver, first determine the molar mass of silver (Ag) which is 107.87 g/mol. Next, calculate the number of moles of silver in 3.68 g by dividing the mass by the molar mass. Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of silver to atoms.
A dozen is equal to 12, so there are 12 x 6.022 x 10^23 silver atoms in a mole. The number of dozens of silver atoms in the piece of jewelry would depend on the weight of the jewelry and the molar mass of silver.
To find the number of atoms in the sample, you would first calculate the number of moles of silver in 1 x 10^-8 g using the molar mass of silver (107.87 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
To calculate the number of silver atoms in 3.76g of silver, you need to use Avogadro's number and the molar mass of silver. The molar mass of silver is 107.87 g/mol. First, calculate the number of moles in 3.76g of silver. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of silver atoms in that many moles.
Silver is an atom.
Silver (Ag) has a molar mass of 107.87g/mol, so by dividing 20.5 by its molar mass, you get how many moles of silver atoms there are in that much silver.(20.5gAg)(1mol/107.87g) = 0.190 moles silver atomsNow, 1 mole = 6.02*1023 (Like a dozen = 12, a mole is just a value.) so if you can't answer in moles, just multiply 0.190 moles by 6.02*10230.190 mol*(6.02*1023/1mol)= 1.14*1023 silver atoms
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Sterling silver is typically about 92.5% silver. To calculate the number of silver atoms in the jewelry piece, you'd first determine the mass of the silver in the jewelry (0.925 * 33.14 g) and then convert this mass to moles of silver (using the molar mass of silver). Finally, you'd use Avogadro's number to convert moles to atoms.
The gram atomic mass of silver is 107.868 and that of gold is 196.967. Equal numbers of gram atoms of different elements contain equal numbers of atoms. Therefore, the mass of gold required to contain twice as many atoms as 2.74 g of gold is (2 X 2.74 X 196.967)/107.868 or 10.0 g of gold, to the justified number of significant digits.
A mole of silver contains approximately 6.022 x 10^23 atoms.
There are 6.022x1023 atoms in a mole. You multiply 6.022x1023 by 8.68, which equals 52.20796x1023 atoms