Silver (Ag) has a molar mass of 107.87g/mol, so by dividing 20.5 by its molar mass, you get how many moles of silver atoms there are in that much silver.
(20.5gAg)(1mol/107.87g) = 0.190 moles silver atoms
Now, 1 mole = 6.02*1023 (Like a dozen = 12, a mole is just a value.) so if you can't answer in moles, just multiply 0.190 moles by 6.02*1023
0.190 mol*(6.02*1023/1mol)= 1.14*1023 silver atoms
2.09*10^22 This is how you figure it out: 3.74g divided by 107.87(the atomic mass of silver). Then you multiply the number you get by 6.022x10^23 (Avogadros number). And that's your answer.
2.17*10^22
The number of atoms of lead is 6,68.10e23.
The gram atomic mass of silver is 107.868 and that of gold is 196.967. Equal numbers of gram atoms of different elements contain equal numbers of atoms. Therefore, the mass of gold required to contain twice as many atoms as 2.74 g of gold is (2 X 2.74 X 196.967)/107.868 or 10.0 g of gold, to the justified number of significant digits.
3.68 grams silver (1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) = 2.05 X 10^22 atoms of silver -----------------------------------------
2.09*10^22 This is how you figure it out: 3.74g divided by 107.87(the atomic mass of silver). Then you multiply the number you get by 6.022x10^23 (Avogadros number). And that's your answer.
2.17*10^22
2.17*10^22
It depends on the weight of the silver in the material. 107.89 g of silver will have 6.023 x 1023 atoms of silver
The number of atoms of lead is 6,68.10e23.
The number of atoms of lead is 6,68.10e23.
The gram atomic mass of silver is 107.868 and that of gold is 196.967. Equal numbers of gram atoms of different elements contain equal numbers of atoms. Therefore, the mass of gold required to contain twice as many atoms as 2.74 g of gold is (2 X 2.74 X 196.967)/107.868 or 10.0 g of gold, to the justified number of significant digits.
3.68 grams silver (1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) = 2.05 X 10^22 atoms of silver -----------------------------------------
The number of atoms is 28,099.10e23.
dose 23 grams of sodium and 238 grams of uranium have equal number of atoms in them
0.24 g
This depends on the percentage of copper in the alloy.If this alloy contain 7,5 % Cu the number of copper atoms is approx. 0,2355.10.e+23.