How many silver atoms are there in 3.70g of silver?

Answer 1

2.09*10^22

This is how you figure it out:

3.74g divided by 107.87(the Atomic Mass of silver). Then you multiply the number you get by 6.022x10^23 (Avogadros number). And that's your answer.

Answer 2

The atomic weight of silver is 107.87, so divide 78.79 by 107.87 to get the number of moles of silver in 78.79 grams, which is 0.7304 moles of silver. The number of atoms in one mole of any substance is 6.022 * 1023. So multiply 0.7304 by this number to get the number of atoms in 78.79 grams of silver.

4.399 * 1023 atoms

Answer 3

The atomic weight of silver is about 107.9. Therefore, the answer to this question is (12.7/107.9) times Avogadro's Number, or 7.09 X 1022 atoms, to the justified number of significant digits.

Answer 4

Silver has 107.87 grams per mole. You have 34.12 grams, so set up a direct proportion where 107.87/1=34.12/x. Solve for x to get 0.316 moles of silver. Now, multiple this by Avogadro's number, which is the number of representative particles of any substance in a mole of that substance. Avogadro's number is 6.02x1023, so that number times 0.316=approx. 1.90x1023 atoms of silver.

Answer 5

The molar mass of silver is 107.868 g/mole. So, in 3.70 g, there are .0343 moles of silver. Using Avogadro's number, it can be seen that there are then 2.066 E22 atoms of silver present.

Answer 6

3.68 grams silver (1 mole Ag/107.9 grams)(6.0-22 X 1023/1 mole Ag)

= 2.05 X 1022 atoms of silver

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Answer 7

3,34 g of silver have 0,186.10e23 atoms.

Answer 8

Some.