What is the mass of 4.50 x 1022 atoms of silver Ag?

Answer 1

To find the mass of 4.50 x 10²² atoms of silver (Ag), first, determine the molar mass of silver, which is approximately 107.87 g/mol. Using Avogadro's number (6.022 x 10²³ atoms/mol), calculate the number of moles: ( \frac{4.50 \times 10^{22} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} \approx 0.0747 \text{ moles} ). Finally, multiply the number of moles by the molar mass: ( 0.0747 \text{ moles} \times 107.87 \text{ g/mol} \approx 8.05 \text{ g} ). Thus, the mass of 4.50 x 10²² atoms of silver is approximately 8.05 grams.