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Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters)

5M C6H12O6 = moles C6H12O6/0.450 liters

= 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6)

= 405.351 grams of glucose ( you do significant figures )

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14y ago

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