For this you need the Atomic Mass of Fe. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.
.410 grams Fe / (55.9 grams) = .00733 moles Fe
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms
This is an incomplete question for several reasons. Iron bromide can be FeBr2 or FeBr3 and this will influence the answer. Also, in order to precipitate silver bromide, one would add silver nitrate, but it isn't stated how much silver nitrate is used. Assuming FeBr2 is used, and there is excess AgNO3, then .... 2AgNO3 + FeBr2 ----> 2AgBr(s) + Fe(NO3) moles FeBr2 = 2.96 g x 1 mol/216 g = 0.0137 moles moles AgBr produced = 2 x 0.0137 = 0.0274 moles mass AgBr produced = 0.0274 moles x 188 g/mole = 5.15 grams <---answer
First you need to find the atomic weights of all the elements involved and add them up (including how many atoms of the same element there are) to find the total molecular mass.Fe = 55.9 grams × 2 atoms = 111.8 gramsO = 16 grams × 3 atoms = 48 grams________________________________________Fe2O3 = 159.8 gramsThen you take the weight of iron in one mole of the compound and divide it by the total weight to get its percent composition.111.8 grams Fe ÷ 159.8 Fe2O3 grams = .6996 = 69.96% Fe in Fe2O3Then we apply this percentage to 639 kg. The thought process is as follows: if there is 69.96% of iron in Fe2O3 by weight, then 69.96% of 639 kg of the substance is iron.69.96% of 639 kg = .6996 × 639 = 447.1 kilograms of Fe in 639 kilograms of Fe2O3
3 mole FeCl2 will react with 6 mole NaOH (stoechiometric mole ratio: 1 FeCl2 to 2 NaOH), so 3 mole FeCl2 (= 6 added -3 used) will be left over.
Use the Avogadro constant 2.50 x 10^20 atoms Fe x ( 1 mol Fe / 6.023 x 10^23 atoms) =4.15 x 10^-4 mol
To convert moles to grams, you need to multiply by the molar mass of the element. The molar mass of Fe (iron) is approximately 55.85 g/mol. For 24.6 moles of Fe, the mass in grams would be 24.6 moles x 55.85 g/mol = 1373.31 grams (approximately).
To find the number of moles in 23 g of Fe, first find the molar mass of Fe by looking up the atomic weight on the periodic table. Fe has a molar mass of approximately 55.85 g/mol. Divide the given mass by the molar mass to find the number of moles: 23 g Fe / 55.85 g/mol = approximately 0.41 moles of Fe.
To find the number of moles of Fe in Fe2O3, first calculate the molar mass of Fe2O3 and O. Then, determine the number of moles of O in the sample. Finally, you can use the stoichiometry of Fe2O3 to find the moles of Fe present. Alternatively, if you know the molar mass of just Fe, you can calculate the moles of Fe by dividing the mass of Fe in the sample by its molar mass.
To determine the number of moles in 223.2 grams of iron (Fe), you will first need to divide the given mass (223.2 g) by the molar mass of iron, which is approximately 55.85 g/mol. This calculation will give you the number of moles of iron in 223.2 grams.
To do this, you need to know the atomic weight of the element you're dealing with, found on any periodic table. The atomic weight is the mass in grams of the element in one mole - this will provide you with a conversion factor. So take the measurement in moles and multiply it by the atomic weight to convert to grams. Really what you're doing is dividing the number by 1 mole, and multiplying it by the equivalent of one mole, the atomic weight. That's the thought process behind unit analysis and how you get your "units to cancel".In this case, the answer is about 882.43 grams Fe.
For this you need the atomic (molecular) mass of FeCl3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. FeCl3=162.4 grams .200 moles FeCl3
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe
To determine the number of moles in 8200 g of Fe, you first need to calculate the molar mass of Fe, which is approximately 55.845 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 8200 g ÷ 55.845 g/mol ≈ 146.7 moles of Fe.
This amount may be different because rust is not a clearly definite compound.
Approx 3.997 moles.
55.8 moles