3 mole FeCl2 will react with 6 mole NaOH (stoechiometric mole ratio: 1 FeCl2 to 2 NaOH), so 3 mole FeCl2 (= 6 added -3 used) will be left over.
Fe2O3
FeCI2 is a combination of iron and hydrochloride. This solution starts out as a yellowish green color. When the equivalence point is reach the solution turns to an orange brown color.
When sodium hydroxide is added to ferrous chloride, a precipitation reaction occurs. This results in the formation of insoluble ferrous hydroxide, which appears as a greenish precipitate. The balanced equation for this reaction is: FeCl2 + 2NaOH → Fe(OH)2 + 2NaCl.
The mass of of iron(II) chloride (anhydrous) is 633,8 grams.
Iron Chloride + Sodium Hydroxide ------> Iron Hydroxide + Sodium Chloride Balanced reaction equations: FeCl3 + 3NaOH ------> Fe(OH)3 + 3NaCl or FeCl2 + 2NaOH ------> Fe(OH)2 + 2NaCl because iron can be either Iron(III)[Fe3+] or Iron(II)[Fe2+]
When iron chloride is mixed with sodium hydroxide, a double displacement reaction occurs. The iron chloride reacts with sodium hydroxide to form iron hydroxide and sodium chloride. The iron hydroxide precipitates out of the solution as a solid, leaving behind a clear liquid containing sodium chloride.
467.52 g NaCl
To determine the grams of NaCl produced from 507 g of FeCl2, we first need to calculate the moles of FeCl2. The molar mass of FeCl2 is approximately 126.75 g/mol. Therefore, 507 g of FeCl2 is about 4.0 moles. According to the balanced equation, 1 mole of FeCl2 produces 2 moles of NaCl. Thus, 4.0 moles of FeCl2 will produce 8.0 moles of NaCl. The molar mass of NaCl is about 58.44 g/mol, so 8.0 moles of NaCl would weigh approximately 467.52 g.
Iron chloride and sodium hydroxide will make iron hydroxide and sodium chloride. For Iron II chloride the equation is: 2NaOH(aq) + FeCl2(aq) --> 2NaCl(aq) + Fe(OH)2(S). For Iron III chloride the equation is: 3NaOH(aq) + FeCl3(aq) --> 3NaCl(aq) + Fe(OH)3(S).
The ionic equation for the reaction is: Fe^2+(aq) + CO3^2-(aq) -> FeCO3(s) and 2Na^+(aq) + 2Cl^-(aq) -> 2NaCl(aq).
The balanced equation for the reaction between phenol (C6H5OH), sodium hydroxide (NaOH), and iron(III) chloride (FeCl3) is: C6H5OH + NaOH + FeCl3 → C6H4(OH)Na + FeCl2 + H2O
Iron (II) chloride and sodium hydroxide react to produce iron (II) hydroxide and sodium chloride. FeCl2(aq) + NaOH(aq) --> Fe(OH)2(s) + NaCl(aq) This is a double replacement/displacement reaction.
Single Displacement
Iron(II) chloride (FeCl2) can be made by reacting iron with hydrochloric acid (HCl). The reaction produces FeCl2 and hydrogen gas (H2). Another method involves the reaction of iron oxide (FeO) with hydrochloric acid to form FeCl2 and water (H2O). FeCl2 can also be obtained by reducing iron(III) chloride (FeCl3) with hydrogen gas (H2) or with another reducing agent.